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hammer [34]
2 years ago
13

A) What minimum velocity must a roller coaster have such that the riders don’t fall out at the top of a loop with a radius of 12

.0 m? [3 marks]
B) What is the normal force a passenger of mass 60.0 kg experiences, If this same roller
coaster has a velocity of 13.0 m/s at the bottom of the loop? [5 marks]
Physics
1 answer:
kramer2 years ago
7 0

Answer: 100 miles per hour

Today, tubular steel tracks and polyurethane wheels allow coasters to travel over 100 miles per hour (160 km/h), while even taller, faster, and more complex roller coasters continue to be built. Hopefully i helped

Explanation:

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Projectile Motion: A pilot drops a package from a plane flying horizontally at a constant speed. Neglecting air resistance, when
love history [14]

Answer:

Explanation:

The package had the same velocity as the plane when it was dropped. Newton's 1st Law says that "an object in motion tends to stay in motion, at the same velocity, in a straight line unless acted on by an outside force".

There only outside force acting on the package was its weight -- that force is straight down. The horizontal velocity that the plane gave the package continued (as Newton said it would), so as it fell, horizontally it kept pace with the plane.

7 0
3 years ago
In Hooke’s law, what does the x represent?
Mice21 [21]

Answer:   C

X = Displacement of the spring

Hooke's law: It states that the applied force F is proportional to the  displacement of spring .

            F ∝ x

            Where, x = displacement of spring in meters

                         F = force, measured in Newtons

In another words The force F is equal to the constant K times the disparagement.

            F = k.x

            Where k is constant and it depends on elastic material.

            Spring has restorative force.  

If the spring moves in opposite direction then,

           F = - k.x

A negative sign indicates that the spring resists and force is to the left. The compression of the spring is greater than the restoring force.  

   Example: A mass 'm' stretches a spring at a displacement x.    

6 0
3 years ago
Two particles, each of mass 7.0 kg, are a distance 3.0 m apart. To bring a third particle, with mass 21 kg, from far away to a r
garri49 [273]

Answer: the external agent must do work equal to -1.3 × 10⁻⁸ J

Explanation:

Given that;

Mass M1 = 7.0 kg

r = 3.0/2 m = 1.5 m

Mass M2 = 21 kg

we know that G = 6.67 × 10⁻¹¹ N.m²/kg²

work done by an external agent W = -2GM2M1 / r

so we substitute

W = (-2 × 6.67 × 10⁻¹¹ × 21 × 7) / 1.5

W = -1.96098 × 10⁻⁸ / 1.5

W = -1.3 × 10⁻⁸ J

Therefore the external agent must do work equal to -1.3 × 10⁻⁸ J

8 0
3 years ago
You do 120 j of work while pulling your sister back on a swing, whose chain is 5.10 m long. you start with the swing hanging ver
Goryan [66]
The work done to pull the sister back on the swing is equal to the increase in potential energy of the sister:
W= \Delta U = mg \Delta h (1)

where m is the sister's mass, g is the gravitational acceleration and \Delta h is the increase in altitude of the sister with respect to its initial position.

By calling \theta the angle of the chain with respect to the vertical, the increase in altitude is given by
\Delta h = L - L \cos \theta = L(1 - \cos \theta) (2)
where L is the length of the chain.

Putting (2) inside (1), we find
W= m g L (1 - \cos \theta)
from which we can find the mass of the sister:
m =  \frac{W}{g L (1 - \cos \theta)} =  \frac{120 J}{(9.81 m/s^2)(5.10 m)(1- \cos 32.0^{\circ})} =15.8 kg
5 0
3 years ago
What happens to matter during chemical changes?
Harrizon [31]
The object that goes through chemical change, changes completely to where you can not change it back to its original form. Physical change you can undo
7 0
3 years ago
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