Answer:
Magnitude of change in momentum = 4.65 kg.m/s
Magnitude of impulse = 4.65 kg.m/s
Magnitude of the average force applied by the bat = 1550 N
Explanation:
Mass of the cricket ball, m = 0.155 kg
Initial velocity of the ball, u = 35.0 m/s
final velocity of the ball after hitting the bat, v = 65.0 m/s
Time of contact, t = 2.00 ms = 2.00 × 10⁻³ s
Now,
Magnitude of change in momentum = Final momentum - Initial momentum
or
Magnitude of change in momentum = ( m × v ) - ( m × u )
or
Magnitude of change in momentum = ( 0.155 × 65 ) - ( 0.155 × 35 )
or
Magnitude of change in momentum = 10.075 - 5.425 = 4.65 kg.m/s
Now, Magnitude of impulse = change in momentum
thus,
Magnitude of impulse = 4.65 kg.m/s
Now,
magnitude of the average force applied by the bat =
or
magnitude of the average force applied by the bat =
or
Magnitude of the average force applied by the bat = 1550 N