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Varvara68 [4.7K]

3 years ago

13

If a person suffers from mysophobia what do they fear?

2 answers:

LenKa [72]3 years ago

4 0

Mysophobia, or the fear of germs, refers to an unhealthy fear of contamination. ... However, if you suffer from mysophobia, these normal concerns become overblown. The phobia is common, affecting even celebrities such as Howie Mandel,

hope this helps!

(:

Liula [17]3 years ago

4 0

Mysophobia is a mental disorder that causes an affected person to have a massive fear of dirt or otherwise contamination. This is also, informally, called "germophobia". Mysophobia and OCD disorder are commonly mistaken for each other.

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A cake is removed from a 350◦F oven and placed on a cooling rack in a 70◦F room. After 30 minutes the cake is 200◦F. When will i

galben [10]

Answer:

350 F to 100 F it take approx 87.33 min

Explanation:

given data

oven = 350◦F

cooling rack = 70◦F

time = 30 min

cake = 200◦F

solution

we apply here Newtons law of cooling

$\frac{dT}{dt}$ = -k(T-Ta)

$\frac{dy}{dt}$ = $\frac{d}{dt}$ (T(t) -Ta)

= $\frac{dT}{dt} -\frac{dTa}{dt} =\frac{dT}{dt}$ = -k(T-Ta)

-ky $\frac{dy}{dt}$ = -ky

T(t) -Ta = (To -Ta) $e^{-kt}$ T(t) = Ta+ (To -Ta) $e^{-kt}$

put her value for time 30 min and T(t) = 200◦F and To =350◦F and Ta = 70◦F

so here

200 = 70 + ( 350 - 70 ) $e^{-k30}$

k = 0.025575

so here for T(t) = 100F

100 = 70 + ( 350 - 70 ) $e^{-0.025575*t}$

time = 87.33 min

so here 350 F to 100 F it take approx 87.33 min

5 0

4 years ago

Measure the length of the arrow in centimeters using correct significant figures.

Zinaida [17]

Based on the very tip of the arrow the best answer would be; 3.3cm

But i could very well be wrong and it may be 3.35, but i would say 3.3 if it just wants to the nearest 10th

6 0

3 years ago

Read 2 more answers

Which statement describes how a machine can help make work easier? It can put out more force than the input force by decreasing

Neko [114]

Answer:

it can be

Explanation:

7 0

3 years ago

A small asteroid with a mass of 1500 kg moves near the earth. At a particular instant the asteroid’s velocity is ⟨3.5 × 104, −1.

zalisa [80]

Answer:

$P_{f}$ =(5.7 x $10^{7$ i - 2.24 x $10^{7$ j) kgm/s

Explanation:

Due to earths gravity, force on asteroid is given by:

$F= \frac{Gm_{1}m_{2} }{r^{2} }$ r^

Plugging in the values, we have

F= [(6.67x $10^{-11}$ )(1500)(5.97 x $10^{24}$ )(8x $10^{6}$ i + 9x $10^{6$ j)] / ((8x $10^{6}$ )² + (9x $10^{6$ )² $)^{1.5}$

F= 2736 i^ + 3078 j^

In order find the final momentum of the Asteroid, apply impulse momentum theorem

$P_{f}$ = $P_{i$ + FΔt

$P_{f}$ = 1500(3.5 x $10^{4$ i - 1.8x $10^{4$ j) + (2736i + 3078j)(1.5x $10^{3$ )

$P_{f}$ =(5.7 x $10^{7$ i- 2.24 x $10^{7$ j)kgm/s

4 0

3 years ago

Colt1911 [192]

B-friction acts in direction opposite to objects motion

5 0

3 years ago

Read 2 more answers