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lesya692 [45]
3 years ago
15

PLEASE HELP ASAPPP

Physics
1 answer:
My name is Ann [436]3 years ago
4 0

Answer:

43.2^{\circ}C

Explanation:

The change in temperature of the sample of alcohol is given by:

\Delta T=\frac{Q}{mC_s}

where

Q = 890 J is the amount of heat provided to the sample

m = 16.6 g is the mass of the sample

C_s = 2.47 J/gC is the specific heat of alcohol

Solving the equation,

\Delta T = \frac{890 J}{(16.6 g)(2.47 J/gC)}=21.7^{\circ}C

And since the initial temperature was

T_i = 21.5^{\circ}C

the final temperature is

T_f = T_i + \Delta T=21.5^{\circ}C + 21.7^{\circ}C=43.2^{\circ}C

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V_2=\frac{Q}{\frac{k.\epsilon_0.A}{d}}

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