Question

PLEASE HELP ASAPPP

Answer 1

Answer:

$43.2^{\circ}C$

Explanation:

The change in temperature of the sample of alcohol is given by:

$\Delta T=\frac{Q}{mC_s}$

where

Q = 890 J is the amount of heat provided to the sample

m = 16.6 g is the mass of the sample

$C_s = 2.47 J/gC$ is the specific heat of alcohol

Solving the equation,

$\Delta T = \frac{890 J}{(16.6 g)(2.47 J/gC)}=21.7^{\circ}C$

And since the initial temperature was

$T_i = 21.5^{\circ}C$

the final temperature is

$T_f = T_i + \Delta T=21.5^{\circ}C + 21.7^{\circ}C=43.2^{\circ}C$