(a) The impulse delivered to the ball by the racket is 5.24 kg.m/s
(b) The work that the racket does on the ball is -35.1 Joule
<h3>Further Explanation</h3>
<u>Given :</u>
mass of ball = m = 0.06 kg
initial velocity = v₁ = -50.4 m/s
final velocity = v₂ = 37.0 m/s
<u>Unknown :</u>
(a) Impulse = I = ?
(b) Work = W = ?
<u>Solution :</u>
<h2>Question (a) :</h2>
In this question , we could use the formula from Second Law of Newton :








<h2>Question (b) :</h2>







<h3>Learn more</h3>
Newton's Law of Motion: brainly.com/question/10431582
Example of Newton's Law: brainly.com/question/498822
<h3>Answer details</h3>
Grade: High School
Subject: Physics
Chapter: Dynamics
Keywords: Newton, Law, Impulse, Work
Assuming there is no force of friction...
F = ma
F = (1300kg)(1.5m/s^2)
F = 1950N
Just multiply mass by acceleration.
1300 x 1.5 = 1950N.
Answer:
Be and Cl
Explanation:
This pair will form an ionic bond because Be is a metal while Cl is a nonmetal.'
Ionic bonds are bonds between nonmetals and metals.
Answer:
∆PE = 749.7 J
At 0.9 m high, PE = 793.8 J
At 1.75 m high, PE = 1543.5 J