The mature stage. I hope this was helpful.
The <span>hardy-weinberg equation is
p2 + 2pq + q2 = 1
where are already given with
c = 0.1 and C = 0.9
SO
p2 = 0.9^2
p2 = 0.81
q2 = 0.01
0.81 + 2pq - 0.01 = 1
2pq = 0.18
The answers are
CC = 0.81
cc = 0.01
Cc = 0.18</span><span />
Answer:
The frequency of the dominant (normal) allele in the population (p) is simply 1 - 0.02 = 0.98 (or 98%). The percentage of heterozygous individuals (carriers) in the population.
Explanation:
(i found it here if you have questions
Hardy-Weinberg - Kansas State Universitywww.k-state.edu › parasitology › biology198 › answers1)
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