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kati45 [8]
3 years ago
9

[Cu(NH3)4](OH)2 Name it

Chemistry
2 answers:
xeze [42]3 years ago
8 0
Tetramminecopper

[iCu(ST4)R](1NG)0
thé answer is a combination which is called a typefncowmmmings
pychu [463]3 years ago
7 0

Answer:

this is a coordination compound perhaps tertramminecopper

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Air is compressed from an inlet condition of 100 kPa, 300 K to an exit pressure of 1000 kPa by an internally reversible compress
ElenaW [278]

Answer:

(a) W_{isoentropic}=8.125\frac{kJ}{mol}

(b) W_{polytropic}=7.579\frac{kJ}{mol}

(c) W_{isothermal}=5.743\frac{kJ}{mol}

Explanation:

Hello,

(a) In this case, since entropy remains unchanged, the constant k should be computed for air as an ideal gas by:

\frac{R}{Cp_{air}}=1-\frac{1}{k}  \\\\\frac{8.314}{29.11} =1-\frac{1}{k}\\

0.2856=1-\frac{1}{k}\\\\k=1.4

Next, we compute the final temperature:

T_2=T_1(\frac{p_2}{p_1} )^{1-1/k}=300K(\frac{1000kPa}{100kPa} )^{1-1/1.4}=579.21K

Thus, the work is computed by:

W_{isoentropic}=\frac{kR(T_2-T_1)}{k-1} =\frac{1.4*8.314\frac{J}{mol*K}(579.21K-300K)}{1.4-1}\\\\W_{isoentropic}=8.125\frac{kJ}{mol}

(b) In this case, since n is given, we compute the final temperature as well:

T_2=T_1(\frac{p_2}{p_1} )^{1-1/n}=300K(\frac{1000kPa}{100kPa} )^{1-1/1.3}=510.38K

And the isentropic work:

W_{polytropic}=\frac{nR(T_2-T_1)}{n-1} =\frac{1.3*8.314\frac{J}{mol*K}(510.38-300K)}{1.3-1}\\\\W_{polytropic}=7.579\frac{kJ}{mol}

(c) Finally, for isothermal, final temperature is not required as it could be computed as:

W_{isothermal}=RTln(\frac{p_2}{p_1} )=8.314\frac{J}{mol*K}*300K*ln(\frac{1000kPa}{100kPa} ) \\\\W_{isothermal}=5.743\frac{kJ}{mol}

Regards.

8 0
3 years ago
In an experiment to determine if the height of a cake is determined by the temperature at which is cooked, measuring the height
Bezzdna [24]

Answer:

  • <u>Dependent variable</u>

Explanation:

In a controlled <em>experiment </em>there will be one independent variable, one dependent variable, and some controlled or constant parameters.

The target of the expermiment is to tes how the dependent variable changes with the independent variable.

So, the scientist will change (manipulate) the independent variable and measure the dependent vabiales.

Here, the temperature will be manipulated (within a range), so this is the independent variable; the height of the cake is the variable whose behavior wants to be determined, so this is the dependent variable. Controlled variables or constants may include the mixture, the size of the pan, the time of cooking, the oven, among others.

6 0
3 years ago
Pls help quickly haha picture shown
Oxana [17]

Answer:

It should be 1, a.

Explanation:

5 0
3 years ago
10. pls pls help me
vagabundo [1.1K]

Answer:

2c2h2+502=4co2+H2O

Explanation:

this is the answer

8 0
3 years ago
What is the term for a process by which molecules of a solvent tend to pass through a semipermeable membrane from a less concent
Lubov Fominskaja [6]
The answer is:
Osmosis
5 0
3 years ago
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