Answer:
y₁ = 0.48
y₂ = 0.52
Explanation:
The method to solve this question is to use Raoult´s law for ideal solutions, which tell us that the vapor pressure of a component A in solution is equal to:
Pa = Xa Pºa
where Pa is the partial pressure of a, xa is its mole fraction, and Pºa is the vapor pressure of pure A.
From here it follows that for a binary solution the total pressure is the sum of the partial pressures of each component.
With vthis in mind we are ready to calculate and solve our question:
P1 = x₁Pº₁ = 0.670 x 20.9Torr = 14.00 torr
P₂ = x₂Pº₂ = (1-0.670) x 45.2 torr = 0.33 x 45.2 torr = 14.91 torr
Ptotal = 14.00 torr + 14.91 torr = 28.91 torr
The composition of the vapor will be given by:
y₁ = Py₁ / Ptotal = 14.00 torr/ 28.91 torr = 0.48
y₂ = 1 - y₁ = 1 - 0.48 = 0.52
Answer:
The radii of potassium is 231 pm
Explanation:
Atomic radii trend along group:
As we move down the group atomic radii increased with increase of atomic number. The addition of electron in next level cause the atomic radii to increased. The hold of nucleus on valance shell become weaker because of shielding of electrons thus size of atom increased.
The given elements are present in same group i.e group one,
Li 152 pm
Na 186 pm
K
Rb 244 pm
The radii of potassium must be greater than sodium and smaller than rubidium.
Thus the value must be between 186 pm - 244 pm
it means the radii of potassium is 231 pm.
Answer:
.0017952905 mol
Explanation:
I hope this helps, I can't promise I got it right, please let me know haha!
Answer:
The equilibrium partial pressure of O2 is 0.545 atm
Explanation:
Step 1: Data given
Partial pressure of SO2 = 0.409 atm
Partial pressure of O2 = 0.601 atm
At equilibrium, the partial pressure of SO2 was 0.297 atm.
Step 2: The balanced equation
2SO2 + O2 ⇆ 2SO3
Step 3: The initial pressure
pSO2 = 0.409 atm
pO2 = 0.601 atm
pSO3 = 0 atm
Step 4: Calculate the pressure at the equilibrium
pSO2 = 0.409 - 2X atm
pO2 = 0.601 - X atm
pSO3 = 2X
pSO2 = 0.409 - 2X atm = 0.297
X = 0.056 atm
pO2 = 0.601 - 0.056 = 0.545 atm
pSO3 = 2*0.056 = 0.112 atm
Step 5: Calculate Kp
Kp = (pSO3)²/((pO2)*(pSO2)²)
Kp = (0.112²) / (0.545 * 0.297²)
Kp = 0.261
The equilibrium partial pressure of O2 is 0.545 atm
Answer:
See explanation
Explanation:
This conversion must go through a sequence of steps as i have shown in the image attached to this answer.
The acetone is converted to propan-2-ol using LiAlH4, THF and acid. The propan-2-ol may be converted to propene by E2 elimination. Addition of HBr yields 2-bromo propane.
The Wurtz reaction converts 2-bromo propane to 2,3- dimethyl butane. This can be brominated in the presence of light to yield 3-bromo-2,3-dimethyl butane. Elimination of HBr using a base leads to the formation of the required product as shown.
