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4 years ago

13

Mr. green is putting lights around 8 windows; each window is 1 and a half metres wide and 2 metres long. how many metres of ligh

ts does he need

1 answer:

rodikova [14]4 years ago

8 0

1 1/2 + 1 1/2 + 2 +2 = a
a(8) = answer

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Noah bought 4 tacos and paid $6. At this rate, how many tacos could he buy for $15? Jada's family bought 50 tacos for a party an

lesya [120]

Answer:

-Noah could buy 10 tacos for $15.

-Jada's tacos were not the same price as Noah's tacos.

Step-by-step explanation:

You can use a rule of three to find the amount of tacos that Noah could buy with $15:

$6 → 4

$15 → x

x=(15*4)/6=10

At this rate, Noah could buy 10 tacos for $15.

Now, to find out if Jada's tacos were the same price as Noah's tacos, you have to find the price per taco in each case by dividing the amount paid by the number of tacos bought:

Noah: 15/10=1.5

Jada: 72/50=1.44

According to this, Jada's tacos were not the same price as Noah's tacos.

7 0

3 years ago

the pencil and the laptop computer are both tools that help writers accomplish their tasks. Follow the clues below to find the y

BartSMP [9]

What you do is divide the sum by 2. You will come out with and answer of 1891. Now, to figure out the years they were invented you take the difference of 192 and divide that in half also. It will come out to 96. Now, you subtract 1891 by 96 and that is the year the pencil was invented (1795=pencil) now with the other half (1891) you add on 96 and you’ll come out with the answer of 1987.

Pencil=1795
Laptop computer=1987.

Hope this helped!

5 0

3 years ago

The following are the temperatures of 10 days in winter in °C.

laila [671]

Answer:

0.9

Step-by-step explanation:

To find the mean temperature, we have to add all of the numbers together and divide that by the amount of numbers there are.

6 + 5 + 3 + -4 + 3 + -3 + 2 + -1 + -2 + 0 = 9

There are 10 numbers.

Our mean, or average, would be 9 / 10 = 0.9

6 0

3 years ago

A popular resort hotel has 300 rooms and is usually fully booked. About 7% of the time a reservation is canceled before the 6:00

kicyunya [14]

Answer:

8.69% probability that at least 285 rooms will be occupied.

Step-by-step explanation:

For each booked hotel room, there are only two possible outcomes. Either there is a cancelation, or there is not. So we use concepts of the binomial probability distribution to solve this question.

However, we are working with a big sample. So i am going to aproximate this binomial distribution to the normal.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X)$ , $\sigma = \sqrt{V(X)}$ .

In this problem, we have that:

A popular resort hotel has 300 rooms and is usually fully booked. This means that $n = 300$

About 7% of the time a reservation is canceled before the 6:00 p.m. deadline with no pen-alty. What is the probability that at least 285 rooms will be occupied?

Here a success is a reservation not being canceled. There is a 7% probability that a reservation is canceled, and a 100 - 7 = 93% probability that a reservation is not canceled, that is, a room is occupied. So we use $p = 0.93$

Approximating the binomial to the normal.

$E(X) = np = 300*0.93 = 279$

$\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{300*0.93*0.07} = 4.42$

The probability that at least 285 rooms will be occupied is 1 subtracted by the pvalue of Z when X = 285. So

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{285- 279}{4.42}$

$Z = 1.36$

$Z = 1.36$ has a pvalue of 0.9131.

So there is a 1-0.9131 = 0.0869 = 8.69% probability that at least 285 rooms will be occupied.

8 0

3 years ago

Is 16% of 40 the same as 40% of 60? Explain your reasoning.

o-na [289]

No 16% of 40 is 32/5 where 40%of 60 is 24.
Hope this helps.

6 0

3 years ago

Read 2 more answers