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const2013 [10]
3 years ago
7

Write the balanced equation for the burning of nonane, c9h20, in air.

Chemistry
1 answer:
Ivanshal [37]3 years ago
3 0
C9H20 + 14O2 --> 9CO2 + 10H2O
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How much sucrose (g) do you need to weight in order to prepare 19.16 g of a 13.1 % (weight percent) solution?
Nonamiya [84]
<span>2.51 grams
   You want to prepare 19.16 g of some solution which will have 13.1% of it's mass being sucrose. So we just need to perform some simple multiplication: 19.16g * 0.131 = 2.50996g
   Rounding to 3 significant figures gives 2.51 g.</span>
3 0
3 years ago
How many dL in 1,000 mL
Anna007 [38]

1,000 mL is the same as 10 dL.

6 0
3 years ago
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Small bodies from which the planets formed
Aleks [24]
Small bodies from which the planets are formed is called : Planetesimal.
Planetesimals that have survived to the current day are valuable to scientists since they contain information about the Solar System's formation.
7 0
3 years ago
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if 100. mL of 0.800 M Na2SO4 is added to 200. mL of 1.20 M NaCl, what is the concentration of Na+ ions in the final solution? As
Black_prince [1.1K]
Compounds Na₂SO₄ and NaCl are mixed together are we are asked to find the concentration of Na⁺ in the mixture 
Na₂SO₄ ---> 2 Na⁺ + SO₄³⁻

1 mol of Na₂SO₄ gives out 2 mol of Na⁺ ions 

the number of Na₂SO₄ moles added - 0.800 M/1000 * 100 ml
                                                         = 0.08 mol
therefore number of Na⁺ ions from Na₂SO₄ = 0.08 * 2 = 0.16 mol

NaCl ----> Na⁺ + Cl⁻ 
1 mol of NaCl gives 1 mol of Na⁺ ions
number of NaCl moles added = 1.20 M/1000 * 200 ml
                                               = 0.24 mol
number of Na⁺ ions from NaCl = 0.24 mol

total number of Na⁺ ions in the mixture = 0.16 mol + 0.24 mol = 0.4 mol
as stated the volumes are additive, 
therefore total volume  = 100 ml + 200 ml = 300 ml 
the concentration of Na⁺ ions = number of moles / volume 
                                              = 0.4 mol/ 0.3 dm³
concentration of Na⁺ = 1.33 mol/dm³
5 0
3 years ago
Convert 78.9 kJ into calories Can you also explain how pls? ty
Naddik [55]

Explanation:

1 kJ = 238.85 cal and

1 cal = 0.004187 kJ

so it will be 78.9×238.85 = <em><u>1</u></em><em><u>8</u></em><em><u>,</u></em><em><u>8</u></em><em><u>4</u></em><em><u>4</u></em><em> </em>calories

78.9 Kilojoules (kJ) = 18,844 Calories (IT) (cal)

3 0
3 years ago
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