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Mashcka [7]
2 years ago
13

X+2y=12. what does x equal​

Mathematics
1 answer:
PilotLPTM [1.2K]2 years ago
4 0

Answer:

x = -2y + 12

Step-by-step explanation:

Let's solve for x.

x + 2y = 12

Step 1: Add -2y to both sides.

x + 2y + −2y = 12 + −2y

x = −2y + 12

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The answer is B.
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Solve the equation by completing the square. Round to the nearest hundredth if necessary. x2 – x – 7 = 0
Tanzania [10]
2x-x-7=0

3x-7=0

add 7 to 7 and 0, so then we cross out 7-7, and then

3x=7, bc u change the subtraction to addition, sr if thst doesn't make sense but 3x=7 is the answer
8 0
3 years ago
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Salina's age is one-quarter the age of her aunt. If a represents her aunt's age, which expression represents Salina's
alukav5142 [94]

Answer:

D. A over 4

Step-by-step explanation:

One quarter is equal to \frac{1}{4}. If her aunt is age 'a', than Salina's age is a/4

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4 0
3 years ago
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Determine the equivalent system for the given system of equations.<br> 4x - 5y = 2<br> 3x - y = 8
kondor19780726 [428]
4x − 5y = 2
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4 0
3 years ago
The final scores from the last five games of two basketball teams are given. Jumping Jackrabbits: 70, 65, 72, 80, 73 Leaping Liz
scoundrel [369]

Using the Mean Absolute Deviation(MAD) concept, it is found that:

a) The Jumping Jackrabbits have a MAD of 3.6 and the Leaping Lizards of 6.8.

b) The MAD is lower for the Jumping Jackrabbits then for the Leaping Lizards, hence their scores are more consistent.

<h3>What is the mean absolute deviation of a data-set?</h3>

  • The mean of a data-set is given by the sum of all observations divided by the number of observations.
  • The mean absolute deviation(MAD) of a data-set is the sum of the absolute value of the difference between each observation and the mean, divided by the number of observations.
  • The mean absolute deviation represents the average by which the values differ from the mean.

Item a:

For the Jumping Jackrabbits, the mean and MAD are given by:

M = (70 + 65 + 72 + 80 + 73)/5 = 72

MAD = (|70 - 72| + |65 - 72| + |72 - 72| + |80 - 72| + |73 - 72|)/5 = 3.6.

For the Leaping Lizards, the mean and the MAD are given by:

M = (61 + 47 + 70 + 63 + 54)/5 = 59

MAD = (|61 - 59| + |47 - 59| + |70 - 59| + |63 - 59| + |54 - 59|)/5 = 6.8.

The Jumping Jackrabbits have a MAD of 3.6 and the Leaping Lizards of 6.8.

Item b:

The MAD is lower for the Jumping Jackrabbits then for the Leaping Lizards, hence their scores are more consistent.

More can be learned about the Mean Absolute Deviation(MAD) concept at  brainly.com/question/3250070

#SPJ1

4 0
2 years ago
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