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PSYCHO15rus [73]

4 years ago

15

Calculate the electrical energy expended in a device across which the circuit voltage drops by 50 volts in moving a charge of 6

coulombs.

2 answers:

solmaris [256]4 years ago

5 0

1 volt = 1 joule per coulomb 50 volts = 50 joules per coulomb 50 joules/coulomb times 6 coulombs = 300 joules

olasank [31]4 years ago

4 0

$I=\dfrac{Q}{t} \\ \\ \\ W=VIt=V\dfrac{Q}{t}t=VQ=50\times 6=300$

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3 years ago

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geniusboy [140]

1. Amperes, is the SI unit (also a fundamental unit) responsible for current.

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Rearrange for Δq

I x Δt = Δq

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Δq = 0.0075

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3. So we know that the end resistances will be equal so:

ρ = RA/L

ρL = RA

ρL/A = R

Now we can set up two equations one for the resistance of the aluminum bar and one for the copper: Where 1 represents aluminum and 2 represents copper

$\frac{p1L1}{A1} = \frac{p2L2}{A2}\\$

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$\frac{A2(\frac{P1L1}{A1}) }{P2} = L2$

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3 years ago

¿Por qué en algunas partes el agua tiene mayor presión?

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Cuando la presión aumenta en el agua, disminuye el punto de fusión del hielo. Ósea esta a temperatura muy alta.

Espero que esto te ayude y no me haya confundido

7 0

3 years ago

You hold a metal block of mass 40 kg above your head at a height of 2 m.

Kitty [74]

Answer:

The work done by gravity is 784 J.

Explanation:

Given:

Mass of the block is, $m=40\ kg$

Height to which it is raised is, $h=2\ m$

Acceleration due to gravity is, $g=9.8\ m/s^2$

Now, work done by gravity is equal to the product of force of gravity and the distance moved in the direction of gravity. So,

$\textrm{Work by gravity}=F_g\times h$

Force of gravity is given as the product of mass and acceleration due to gravity.

$\therefore F_g=mg=40\times 9.8=392\ N$ . Now,

$\textrm{Work by gravity}=F_g\times h=392\times 2=784\ J$

Therefore, the work done by gravity is 784 J.

5 0

3 years ago