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PSYCHO15rus [73]

3 years ago

15

Calculate the electrical energy expended in a device across which the circuit voltage drops by 50 volts in moving a charge of 6

coulombs.

2 answers:

solmaris [256]3 years ago

5 0

1 volt = 1 joule per coulomb 50 volts = 50 joules per coulomb 50 joules/coulomb times 6 coulombs = 300 joules

olasank [31]3 years ago

4 0

$I=\dfrac{Q}{t} \\ \\ \\ W=VIt=V\dfrac{Q}{t}t=VQ=50\times 6=300$

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A 26-g steel-jacketed bullet is fired with a velocity of 630 m/s toward a steel plate and ricochets along path CD with a velocit

Alecsey [184]

Answer:

F = - 3.53 10⁵ N

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This problem must be solved using the relationship between momentum and the amount of movement.

I = F t = Δp

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t = d / v

Reduce SI system

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d = 50 mm ( 1m/ 1000 mm) = 50 10⁻³ m

Let's calculate

t = 50 10⁻³ / 600

t = 8.33 10⁻⁵ s

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F = m (v-vo) / t

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F = - 3.53 10⁵ N

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3 years ago

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2 years ago

An inattentive driver is traveling 18.0 m/s when he notices a red light ahead. his car is capable of decelerating at a rate of 3

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Speed of the car given initially

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Now after applying brakes the distance covered by the car before it stops is given by kinematics equation

$v_f^2 - v_i^2 = 2 a s$

here

vi = 18 m/s

vf = 0

a = - 3.35

so now we will have

$0^2 - 18^2 = 2*(-3.35)(s)$

$s = 48.35 m$

So total distance after which car will stop is

$d = d_1 + d_2$

$d = 48.35 + 3.6 = 51.95 m$

So car will not stop before the intersection as it is at distance 20 m

3 0

3 years ago