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PSYCHO15rus [73]
3 years ago
15

Calculate the electrical energy expended in a device across which the circuit voltage drops by 50 volts in moving a charge of 6

coulombs.
Physics
2 answers:
solmaris [256]3 years ago
5 0
1 volt = 1 joule per coulomb 50 volts = 50 joules per coulomb 50 joules/coulomb times 6 coulombs = 300 joules
olasank [31]3 years ago
4 0
I=\dfrac{Q}{t} \\  \\  \\ W=VIt=V\dfrac{Q}{t}t=VQ=50\times 6=300
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A 0.500 H inductor is connected in series with a 93 Ω resistor and an ac source. The voltage across the inductor is V = −(11.0V)
bezimeni [28]

Answer:

205 V

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Explanation:

L = Inductance in Henries, (H)  = 0.500 H

resistor is of 93 Ω so R = 93 Ω

The voltage across the inductor is

V_{L} = - IwLsin(wt)

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Current:

I = 11.0 V / wL

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Deriving formula for voltage across the resistor

The derivative of sin is cos

V_{R} = V_{R} cos (wt)

Putting V_{R} = 4.092 V and w = 500 rad/s

V_{R} = V_{R} cos (wt)

    = (4.092 V) (cos(500 rad/s )t)

So the voltage across the resistor at 2.09 x 10-3 s is which means

t = 2.09 x 10⁻³

V_{R} = (4.092 V) (cos (500 rads/s)(2.09 x 10⁻³s))

    =  (4.092 V) (cos (500 rads/s)(0.00209))

    = (4.092 V) (cos(1.045))

    = (4.092 V)(0.501902)

    = 2.053783

V_{R} = 2.05 V

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3) The energy of the photons of an electromagnetic wave is given by
E=hf
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