Ask question

Ask question

All categories

PSYCHO15rus [73]

3 years ago

15

Calculate the electrical energy expended in a device across which the circuit voltage drops by 50 volts in moving a charge of 6

coulombs.

2 answers:

solmaris [256]3 years ago

5 0

1 volt = 1 joule per coulomb 50 volts = 50 joules per coulomb 50 joules/coulomb times 6 coulombs = 300 joules

olasank [31]3 years ago

4 0

$I=\dfrac{Q}{t} \\ \\ \\ W=VIt=V\dfrac{Q}{t}t=VQ=50\times 6=300$

You might be interested in

A skater slides across the ice with an initial velocity of 5.0 m/s. She slows 10 points

zvonat [6]

Explanation:

Given that,

The initial velocity of a skater is, u = 5 m/s

She slows to a velocity of 2 m/s over a distance of 20 m.

We can find the acceleration of skater. It is equal to the rate of change of velocity. So, it can be calculated using third equation of motion as follows :

$v^2-u^2=2as$

a = acceleration

$a=\dfrac{v^2-u^2}{2s}\\\\a=\dfrac{(2)^2-(5)^2}{2\times 20}\\\\a=-0.525\ m/s^2$

So, her acceleration is $0.525\ m/s^2$ and she is deaccelerating. Also, her initial velocity is given i.e. 5 m/s.

7 0

2 years ago

Which statements describe what is occurring at t=5 seconds? Check all that apply

Alex73 [517]

Answer: The object changed directions

The object sped up

Explanation:

7 0

3 years ago

The resistivity of gold is at room temperature. A gold wire that is 0.9 mm in diameter and 14 cm long carries a current of 940 m

IgorC [24]

Answer:

0.0360531138247 V/m

Explanation:

$\rho$ = Resistivity of gold = $2.44\times 10^{-8}\ \Omega .m$ (General value)

I = Current = 940 mA

d = Diameter = 0.9 mm

A = Area = $\dfrac{\pi}{4}d^2$

E = Electric field

Resistivity is given by

$\rho=\dfrac{EA}{I}\\\Rightarrow E=\dfrac{\rho I}{A}\\\Rightarrow E=\dfrac{2.44\times 10^{-8}\times 940\times 10^{-3}}{\dfrac{\pi}{4}(0.9\times 10^{-3})^2}\\\Rightarrow E=0.0360531138247\ V/m$

The electric field in the wire is 0.0360531138247 V/m

6 0

3 years ago

Read 2 more answers

A solar reflector is made using 31 identical triangular-shaped mirrors, each having sides . What is the total surface area of th

Stels [109]

Complete Question

Question 18 (3 points) Solve the problem. (3 points) A solar reflector is made using 31 identical triangular-shaped mirrors, each having sides 2.4m, 2. 3m, 1.5 m. What is the total surface area of the reflector?

A) 33 m2

B) 86 m2

C) 52 m2

D) 34 m2

Answer:

The value is $Area =2.78 \ m^2$

Explanation:

From the question we are told that

The sides are a = 2.4 m

b = 2.3 m

c = 1.5 m

Generally the semi perimeter is mathematically represented as

$s = \frac { a + b + c }{2 }$

=> $s = \frac { 2.4 + 2.3 + 1.5 }{2 }$

=> $s =3.1 \ m$

Generally the using Heron's formula we have that the surface are a is mathematically represented as

$Area = \sqrt{S (S - a) (S - b )(S - c ) }$

=> $Area = \sqrt{3.1 (3.1 - 2.4) (3.1 - 2.3 )(3.1 - 1.5 ) }$

=> $Area =2.78 \ m^2$

6 0

2 years ago

What is convectional current?.... .

fiasKO [112]

Answer:

Convection is the transfer of heat from one place to another along with the motion of the object's particles. Water is a poor conductor. However, when the bottom water is heated, it turns out that the top water is also hot. This means that there is another way of transferring heat to the water, namely convection.

8 0

2 years ago