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Reil [10]
3 years ago
13

Charles's law is an experimental gas law that shows the relationship between the temperature of a gas and its corresponding volu

me. Based on the picture above, which model below correctly represents Charles's law?

Chemistry
1 answer:
GREYUIT [131]3 years ago
3 0

Answer:

B. (Linear graph with positive slope)

Explanation:

The picture above showing that  

1. T2 is higher than T1

2. V2 is higher than V2

From this, we can conclude that the relationship for temperature (T) and volume(V) is positive. That means a higher temperature will result in a higher volume.  

Since the relationship positive, the graph will have a positive slope. We can't prove if the graph should be linear or exponential since we don't have the exact number of the experiment.

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Sergio [31]

Answer:

C. The Protons

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3 years ago
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Trans fats: Think about how the prefix trans- is used in naming alkenes.
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In an alkene, cis and trans isomers are possible because the double band is rigid, cannot rotate, has groups attached to the carbons of the double bond that are fixed relative to each other, and only occurs with double bonds-possibility that molecule will have different geometries; two different molecules with slightly different properties. 
-Trans-2 ends of chain across the double bond.
While naming Cis-Trans isomers the prefix cis or trans are placed in front of the alkene name when there are cis-trans isomers. 
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2 years ago
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A functional group is a specific arrangement of atoms in an organic compound that is capable of characteristic reactions
dolphi86 [110]

Answer:

True

Explanation:

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3 years ago
What element decreases its oxidation number in this reaction
MissTica

Where’s the reaction?

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3 years ago
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A bomb calorimeter has a heat capacity of 675 J/°C and contains 925 g of water. If the combustion of 0.500 mole of a hydrocarbon
ikadub [295]

<u>Answer:</u> The enthalpy of the reaction is 269.4 kJ/mol

<u>Explanation:</u>

To calculate the heat absorbed by the calorimeter, we use the equation:

q_1=c\Delta T

where,

q = heat absorbed

c = heat capacity of calorimeter = 675 J/°C

\Delta T = change in temperature = T_2-T_1=(53.88-24.26)^oC=29.62^oC

Putting values in above equation, we get:

q_1=675J/^oC\times 29.62^oC=19993.5J

To calculate the heat absorbed by water, we use the equation:

q_2=mc\Delta T

where,

q = heat absorbed

m = mass of water = 925 g

c = heat capacity of water = 4.186 J/g°C

\Delta T = change in temperature = T_2-T_1=(53.88-24.26)^oC=29.62^oC

Putting values in above equation, we get:

q_2=925g\times 4.186J/g^oC\times 29.62^oC=114690.12J

Total heat absorbed = q_1+q_2

Total heat absorbed = [19993.5+114690.12]J=134683.62J=134.7kJ

To calculate the enthalpy change of the reaction, we use the equation:

\Delta H_{rxn}=\frac{q}{n}

where,

q = amount of heat absorbed = 134.7 kJ

n = number of moles of hydrocarbon = 0.500 moles

\Delta H_{rxn} = enthalpy change of the reaction

Putting values in above equation, we get:

\Delta H_{rxn}=\frac{134.7kJ}{0.500mol}=269.4kJ/mol

Hence, the enthalpy of the reaction is 269.4 kJ/mol

6 0
3 years ago
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