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hjlf
3 years ago
12

How hard is Stoichiometry? Just want to know since I'm about to do a lesson on it..

Chemistry
1 answer:
DanielleElmas [232]3 years ago
6 0
Stoichiometry is not really hard if you are good with your numbers. All you have to do is pay close attention and follow you teacher because if you don't you will end up like me not knowing what you are doing. Listen and pay real close attention and I can guarantee you it will be just fine!
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Explain the term respiration and how this process increases the percentage of carbon dioxide in the atmosphere.
sammy [17]

Answer:

Please find the explanation to this question below.

Explanation:

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3 years ago
Which of the following describes the arrangement of valence electrons in a bond between H and F?
Sloan [31]
C; The Valence electrons spend more time around the atom of F
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Determine the rate law, including the values of the orders and rate law constant, for the following reaction using the experimen
olga55 [171]

Answer: Rate law=k[A]^1[B]^2, order with respect to A is 1, order with respect to B is 2 and total order is 3. Rate law constant is 3L^2mol^{-2}s^{-1}

Explanation: Rate law says that rate of a reaction is directly proportional to the concentration of the reactants each raised to a stoichiometric coefficient determined experimentally called as order.

Rate=k[A]^x[B]^y

k= rate constant

x = order with respect to A

y = order with respect to A

n = x+y = Total order

a) From trial 1: 1.2\times 10^{-2}=k[0.10]^x[0.20]^y    (1)

From trial 2: 4.8\times 10^{-2}=k[0.10]^x[0.40]^y    (2)

Dividing 2 by 1 :\frac{4.8\times 10^{-2}}{1.2\times 10^{-2}}=\frac{k[0.10]^x[0.40]^y}{k[0.10]^x[0.20]^y}

4=2^y,2^2=2^y therefore y=2.

b) From trial 2: 4.8\times 10^{-2}=k[0.10]^x[0.40]^y    (3)

From trial 3: 9.6\times 10^{-2}=k[0.20]^x[0.40]^y   (4)

Dividing 4 by 3:\frac{9.6\times 10^{-2}}{4.8\times 10^{-2}}=\frac{k[0.20]^x[0.40]^y}{k[0.10]^x[0.40]^y}

2=2^x,2=2^1, x=1

Thus rate law is Rate=k[A]^1[B]^2

Thus order with respect to A is 1 , order with respect to B is 2 and total order is 1+2=3.

c) For calculating k:

Using trial 1:  1.2\times 10^{-2}=k[0.10]^1[0.20]^2

k=3 L^2mol^{-2}s^{-1}.



6 0
3 years ago
In your own words, explain how multiple approaches to a scientific investigation can be used to obtain the same result. Provide
aleksandr82 [10.1K]

Answer:B

Explanation:

5 0
3 years ago
Write one common thing between condensation and hydrolysis ?​
serious [3.7K]

Answer:

The common thing is the compound water

Explanation:

in condensation h2O is expelled while in hydrolysis water is used or added

8 0
2 years ago
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