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Inessa [10]
3 years ago
13

PLEASE HELP ASAP!!!

Mathematics
1 answer:
ANTONII [103]3 years ago
8 0
C is the answer have a great day
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Prove that if one solution for a quadratic equation of theform x2 + bx + c = 0 is rational (where b and c are rational),then the
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The other solution of the given equation x² + bx + c = 0   is also rational number.

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Here, given: ax² + bx + c = 0 is a quadratic equation

Also, one solution  (r)  of equation is RATIONAL.

To show: The other solution (s)  is also RATIONAL

Now, here: as x² + bx + c = 0

Since r and s are the two given solutions, the given equation can be factorized as:

x² + bx + c =  (x -r) (x - s)

Simplifying LHS, we get:

(x -r) (x - s) = x x - r (x) - s (x) +  (r)(s)

                 =  x² + x(-r - s) +  rs

or, x² + bx + c = x² + x(-r - s) +  rs

Comparing the related terms, we get:

b =  (-r - s)    

⇒  b +  s = - r

or, s  = -r - b

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⇒ s is a RATIONAL NUMBER

Hence, the other solution of the given equation x² + bx + c = 0   is also rational number.

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