H2O is also know as water
<u>Answer:</u> The cross-sectional area of the cylindrical rod is 
<u>Explanation:</u>
We are given a cylindrical rod whose cross-sectional area will be in the form of circle.
To calculate the area of circle, we use the equation:

where,
r = radius of the rod =
(Conversion factor: 1 m = 1000 mm)
Putting values in above equation, we get:

Hence, the cross-sectional area of the cylindrical rod is 
:<span> </span><span>2 C10H7OH + 23 O2 → 20 CO2 + 8 H2O
hope it helps</span>
Answer:
They are all formed in acidic solution.
Explanation:
The diagram for hemiacetal, acetal and imine is shown in the diagram below and a star is placed on the three of them since they are all form in acidic solution.
From the diagram; reaction of methanol with propanal leads to formation of hemiacetal. From CH₃OH(methanol), one hydrogen attaches itself to the Oxygen double bond on the propanal to form a new hydroxyl group, the other methoxyl (-O-CH₃) from methanol attaches itself to other part of the propanal.
The further addition of methanol to Hemiacetal yields to Acetal.
Imines are formed by Mannich Reaction which is the reaction of propanal with amine group and which is followed by the dehydration with a Schiff base.
Answer:
The see explanation
Explanation:
In this case, we have an <u>"amine"</u> group in the dopamine structure. So, the dopamine will act as a <u>"base"</u>. A base is a substance that has the ability to <u>accept hydrogens</u>, therefore, the
will take hydrogen from the water molecule. Additionally, the water will produce the
ion and the
will be converted into
.
See figure 1
I hope it helps!