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The work and heat transfer isothermal internally reversible process.
An isothermal procedure is a thermodynamic procedure in which the temperature of a gadget stays consistent. The transfer of heat into or out of the gadget occurs so slowly that thermal equilibrium is maintained. The melting of ice at 0 diploma is an example of isothermal technique. The reaction in a warmth pump is an example of isothermal manner. In Isothermal manner temperature is constant for the duration of the procedure and follows Boyles regulation.
Given,
Gas at initially P1= 2.8 bar
P2 = 14 bar
isothermal reversible process,
Compressed pressure at 60°C
(a) R = 134a
For Refrigerant 134a R134a
At P1 = 14 bar T1 = 600C
S1 = 0.9389 KJ/Kg K
V1 = 264.64 KJ/kg
At
P2 = 2.8 bar T2 = 600C
S2 = 1.1142 KJ/Kg K
V2 = 278.56 KJ/kg
T = 60 + 273 = 333K
Q= 2 Tds
2 Q=T ſ ds
= T(S2-S1)
= 333 ( 1.1142 - 0.9389 )
= 58.3749 KJ/Kg
Heat transfer Q = 58.3749 KJ/Kg
(b) air as an ideal gas.
Q= 2 Tds
2 Q=T ſ ds
= T(S2-S1)
=T-R In P2 P1
= 333 * -0.287 In 2.8 14
= 153.81 KJ/Kg
Heat transfer Q = 153.81 KJ/Kg
W = Q - ΔV
= 28.3749 - (278.56-264.64)
= 14.4549 KJ/Kg
Work W = 14.4549 KJ/Kg
Learn more about isothermal process here:-brainly.com/question/17097259
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