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Ugo [173]
4 years ago
7

Choose all the answers that apply. Heat: is the same as temperature can be increased by compression is transferred in solids by

conduction is transferred in liquids by convection requires a medium
Physics
2 answers:
Otrada [13]4 years ago
5 0

Answer:

C and D are correct

Explanation:

They both show good examples of what heat is

olga55 [171]4 years ago
3 0

Answer:

The question can be re-framed as:

Heat:

⇒a) is the same as temperature

⇒b) can be increased by compression.

⇒c) is transferred in solids by conduction.

⇒d) is transferred in liquids by convection

⇒e) requires a medium.

Option c and d are correct choices.

Explanation:

⇔Heat is a form of energy which can be transferred from higher temperature to lower temperature.

So heat is not the same as temperature.

Where as temperature is the measure of Kinetic energy  possessed by the particles of an object.

⇔As far as the Ideal Gas Law is concerned any gas will tend to heat up as it is compressed and cool down when it expands.

Heat can't be increased by compression its transfer of energy.

⇔Conduction is the transfer of heat between substances that are in direct contact with each other.

Heat is transferred in solids by conduction.

⇔Heat is transferred from hot places to cold places by convection. Convection occurs when warmer areas of a liquid or gas rise to cooler areas in the liquid or gas.

Heat is transferred in liquids by convection.

⇔Heat does not requires a medium for its transfer as in case of radiation where heat is transferred by electromagnetic waves.

Heat doesn't requires a medium for its transfer.

So our correct answer comprises:

Option C and option D that is Heat "is transferred in solids by conduction" and "is transferred in liquids by convection".

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Why? I need some help I would like at least 1 answer <br><br><br> Thanks,<br> Vishnu
siniylev [52]
I think the 3rd one is the answer
8 0
3 years ago
Skateboard A Force: 33 N Time: 0.12 s Skateboard B Force: 33 N Time: 0.57 s Skateboard C Force: 33 N Time: 0.78 s Which skateboa
nata0808 [166]
The impulse is given by the magnitude of the force times the time interval:
I= F \Delta t
We can see that the force F of the 4 skateboard is always the same (33 N), this means that the skateboard with greatest impulse is the one with the largest time interval, so skateboard C).
7 0
3 years ago
Read 2 more answers
10) Two students want to use a 12-meter long rope to create standing waves. They first measure the speed at which a single wave
zhannawk [14.2K]

Answer:

To create a second harmonic the rope must vibrate at the frequency of 3 Hz

Explanation:

First we find the fundamental frequency of the rope. The fundamental frequency is the frequency of the rope when it vibrates in only 1 loop. Therefore,

f₁ = v/2L

where,

v = speed of wave = 36 m/s

L = Length of rope = 12 m

f₁ = fundamental frequency

Therefore,

f₁ = (36 m/s)/2(12 m)

f₁ = 1.5 Hz

Now the frequency of nth harmonic is given in general, as:

fn = nf₁

where,

fn = frequency of nth harmonic

n = No. of Harmonic = 2

f₁ = fundamental frequency = 1.5 Hz

Therefore,

f₂ = (2)(1.5 Hz)

<u>f₂ = 3 Hz</u>

5 0
3 years ago
A weight of 30.0 N is suspended from a spring that has a force constant of 220 N/m. The system is undamped and is subjected to a
Nimfa-mama [501]

Answer:

F_0 = 393 N

Explanation:

As we know that amplitude of forced oscillation is given as

A = \frac{F_0}{ m(\omega^2 - \omega_0^2)}

here we know that natural frequency of the oscillation is given as

\omega_0 = \sqrt{\frac{k}{m}}

here mass of the object is given as

m = \frac{W}{g}

\omega_0 = \sqrt{\frac{220}{\frac{30}{9.81}}}

\omega_0 = 8.48 rad/s

angular frequency of applied force is given as

\omega = 2\pi f

\omega = 2\pi(10.5) = 65.97 rad/s

now we have

0.03 = \frac{F_0}{3.06(65.97^2 - 8.48^2)}

F_0 = 393 N

6 0
3 years ago
A 1060-kg car moving west at 16 m/s collides with and locks onto a 1830-kg stationary car. determine the velocity of the cars ju
iren [92.7K]
M1U1 + M2V2 = (M1+M2)V, where M1 is the mass of the moving car, M2 is the mass of the stationary car, U1 is the initial velocity, and V is the common velocity after collision.
therefore; 
(1060× 16) + (1830 ×0) = (1060 +1830) V
 16960 = 2890 V
      V = 5.869 m/s
The velocity of the cars after collision will be 5.689 m/s
5 0
3 years ago
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