Find the magnitude of the resultant force and the angle it makes with the positive x-axis. (Let a = 200 N and b = 400 N. Round y
our answers to one decimal place.)
1 answer:
Answer: R = 346.4N and angle 30° to the horizontal negative axis
Explanation:
To find the resultant force, we need to sum up the forces on the vertical and horizontal axis.
For the horizontal axis;
Rx = -b + acos60
Rx = -400N +200cos60
Rx = -400N +100N
Rx = -300N
For the vertical axis;
Ry = asin60 = 200sin60
Ry = 173.2N
The resultant force R can be given as;
R = √(Rx^2 +Ry^2)
R = √((-300)^2 + 173.2^2)
R = 346.4N
Angle z can be written as
Tanz = Ry/Rx
z = taninverse (Ry/Rx)
z = taninverse (173.2/300)
z = 30°
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if we launch a projectile from some initial height h all you need to do is add this initial elevation
Answer:
(a) 1.093 rad/s^2
(b) 4.375 rad/s
(c) 8.744 rad/s
(d) 67.845 rad
Explanation:
initial angular velocity, ωo = 0
time, t = 8s
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(a) Let α be the angular acceleration.
Use second equation of motion for rotational motion
By substituting the values
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(b) The average angular velocity is defined as the ratio of total angular displacement to the total time taken .
Average angular velocity = 35 / 8 = 4.375 rad/s
(c) Let ω be the instantaneous angular velocity at t = 8 s
Use first equation of motion for rotational motion
ω = ωo + αt
ω = 0 + 1.093 x 8 = 8.744 rad/s
(d) Let in next 5 seconds the angular displacement is θ.
By substituting the values
θ = 8.744 x 5 + 0.5 x 1.093 x 5 x 5
θ = 67.845 rad