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Lilit [14]
4 years ago
13

When an apple falls towards the earth,the earth moves up to meet the apple. Is this true?If yes, why is the earth's motion not n

oticeable?​
Physics
2 answers:
Anarel [89]4 years ago
6 0

Answer:

True, because unlike the apple we don't have a large as$ refrence point (the earth is too big to notice being pushed)

Explanation:

Katena32 [7]4 years ago
4 0

Yes, this is true.

-- While the apple is falling, the same gravitational force acts on both the apple and the Earth.

-- The mass of the apple is somewhere in the neighborhood of 1/4 kg.

-- The mass of the Earth is about 5.972 x 10²⁴ kg.

-- Since the Earth has roughly 2.389 x 10²⁶ times as much mass as the apple has, the apple has roughly 2.389 x 10²⁶ greater acceleration than the Earth has, and moves roughly 2.389 x 10²⁶ times as far down as the Earth moves up, before they smack together.

-- That's why you don't notice the Earth's motion.

-- Also, you're standing on the Earth, moving up with it, toward the apple.  Maybe it would be different if you were sitting on the apple, riding it down to the ground, and you were able to notice the motion of the ground coming up to meet you at a speed that's 0.00000000000000000000000000419 of YOUR speed.  

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What would be the result of voltage while joining 2 or more different voltages of batteries with parallel ? and explain me what
cupoosta [38]
That's not a good idea. You don't want to connect batteries with different voltages in parallel. What happens is large currents among the batteries themselves, and some of the batteries quickly die.

When the batteries are connected in SERIES, they behave as a single battery whose voltage is the sum of their individual voltages.
3 0
4 years ago
A baseball of mass 1.23 kg is thrown at a speed of 65.8 mi/h. What is its kinetic energy?
frosja888 [35]

Given:

The mass of the ball is

m=1.23\text{ kg}

The speed of the ball is

\begin{gathered} v=65.8\text{ mi/h} \\  \end{gathered}

Required: calculate the kinetic energy of the baseball

Explanation: to calculate the kinetic energy of a body we will use the formula as

K.E=\frac{1}{2}mv^2

first, we convert velocity from mi/h into m/s.

we know that

1\text{ mi=1609.34 m}

and

1\text{ h=3600 sec}

then the velocity is

\begin{gathered} v=\frac{65.8\times1602.34\text{ m}}{3600\text{ s}} \\ v=29.29\text{ m/s} \end{gathered}

now plugging all the values in the above formula, we get

\begin{gathered} K.E=\frac{1}{2}mv^2 \\ K.E=\frac{1}{2}\times1.23\text{ kg}\times(29.29\text{ m/s})^2 \\ K.E=527.61\text{ J} \end{gathered}

Thus, the kinetic energy of the baseball is

527.61\text{ J}

4 0
2 years ago
PLEASE HELP!!! 50 points!!!!!! SEE ATTACHMENT!!! In which direction is there a net force of 200 N? left, right, up, down
Sladkaya [172]

The answer is right. The point and the 200 N sign maybe on the left side but the direction can be going right. I just took the quiz today, I wouldn't give the wrong answer cause i'm not a liar.  -_-

5 0
3 years ago
Read 2 more answers
A particle moves along a straight path through displacement while force acts on it. (Other forces also act on the particle.) Wha
allsm [11]

a) c = 1.85

b) c = 0.8

c) c = 2.33

Explanation:

a)

The displacement of the particle is given by

d=2.2i+cj

While the force applied on the particle is

F=3.2i-3.8 j

So we have a problem in 2-dimensions.

The work done on the particle is given by the scalar product between force and displacement:

W=F\cdot d (1)

Here the work done on the particle is zero, so

W = 0

Therefore from eq(1) we find:

0=(3.2i-3.8j)\cdot (2.2i+cj)=7.04-3.8c\\3.8c=7.04\\c=\frac{7.04}{3.8}=1.85

b)

In this problem, the work done on the particle is

W=4.0 J

The force and displacement are still

d=2.2i+cj (displacement)

F=3.2i-3.8 j (force)

Therefore, by calculting the scalar product between force and displacement and equating it to the work done (4.0 J), we find:

W=F\cdot d

4.0 =(3.2i-3.8j)\cdot (2.2i+cj)=7.04-3.8c\\3.8c=3.04\\c=\frac{3.04}{3.8}=0.8

c)

In this problem instead, the work done on the particle is negative:

W=-1.8 J

As before, the force and displacement are

d=2.2i+cj (displacement)

F=3.2i-3.8 j (force)

And so again, we calculate the scalar product between  force and displacement and we equate it to the work done on the particle, -1.8 J.

Doing so, we find:

W=F\cdot d

-1.8=(3.2i-3.8j)\cdot (2.2i+c)=7.04-3.8c\\3.8c=8.84\\c=\frac{8.84}{3.8}=2.33

7 0
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Kirk wants to know if someone his height will go faster on a bike with a larger frame. What should he do next in order to follow
bearhunter [10]

Answer:

The answer is A but I could be wrong

8 0
3 years ago
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