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3 years ago

Friction and air resistance are forces that always:

Physics

1 answer:

Softa [21]3 years ago

7 0

2 act in the opposite direction. To an objects motion, tending to slow it down

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A thread holds a 1.5-kg and a 4.50-kg cart together. After the thread is burned, a compressed spring pushes the carts apart, giv

maksim [4K]

Answer:

c. 8.67 cm/s

Explanation:

From the law of conservation of momentum,

Total momentum before the thread was burned = Total momentum after was burned

mu + m'u' = mv + m'v'...................... Equation

Where m = mass of the heavier cart, m' = mass of the lighter cart, u = initial velocity of the bigger cart, u' = initial velocity of the smaller cart, v = final velocity of the bigger cart, v' = final velocity of the smaller cart.

Note: Both cart where momentarily at rest, as such u = u' = 0. i.e the total momentum before the thread was burn = 0

And assuming the left is positive,

We can rewrite equation 1 as

mv + m'v' = 0............................................ Equation 2

Given: m = 4.5 kg, m' = 1.5 kg, v' = 26 cm/s

Substitute into equation 2,

4.5v + 1.5(26) = 0

4.5v + 39 = 0

4.5v = -39

v = -39/4.5

v = -8.67 cm/s.

Note: v is negative because it moves to right.

Hence the velocity of the 4.5 kg cart = 8.67 cm/s.

The right option is c. 8.67 cm/s

7 0

3 years ago

One way to increase acceleration is by

Kay [80]

Answer:

One way to increase acceleration is by changing the velocity.

6 0

3 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!! I CANNOT RETAKE THIS AND I NEED ALL CORRECT ANSWERS ONLY!!!

Travka [436]

Yes you are correct...I dont think you need to do this? You are getting them all right but now your just wasting points..

But anyways you are correct. ♡♡

5 0

4 years ago

9. Batman (mass=91 kg) jumps straight down from a bridge into a boat (mass=510 kg) in which a criminal is fleeing. The velocity

Ierofanga [76]

Answer:

V = 9.33 m/s

Explanation:

Given that,

Mass of the batsman, $m_1=91\ kg$

Mass of the boat, $m_2=510\ kg$

Initial speed of the boat, v = 11 m/s

Let V is the velocity of the boat after Batman lands in it. The net momentum of the system remains constant. Using the conservation of linear momentum to find it as :

$510\times 11=(91+510)V$

$V=\dfrac{510\times11}{(91+510)}$

V = 9.33 m/s

So, the velocity of the boat after Batman lands in it 9.33 m/s. Hence, this is the required solution.

5 0

3 years ago

If the pressure in a gas is doubled while its volume is held constant, by what factor do vrms change

Nat2105 [25]

Answer is given below

Explanation:

given data

pressure = double

volume = constant

solution

As we know that an Average velocity and rms velocity is directly proportional to square root of PV ..................1

so if we take P is doubled while keeping V constant

than Velocity increases by a factor $\sqrt{2}$

so that Factor = 1.414 for both the cases

8 0

3 years ago