Answer:
The correct answer will be "
".
Explanation:
The time it would take again for current or electricity flows throughout the circuit including its LR modules can be connected its full steady-state condition is equal to approximately 5
as well as five-time constants.
It would be calculated in seconds by:
⇒ 
, where
- R seems to be the resistor function in ohms.
- L seems to be the inductor function in Henries.
Answer:
A. Equal to and Opposite
Explanation:
when there is no External force acting on the system of bodies then Net momentum of the system is Conserved .
Given that there are 2 bodies
Let P₁ as first object's momentum
P₂ as second object's momentum.
Total Momentum =P₁ + P₂
As there is no external force acying on the system
Change in the Total momentum is zero
so,
0 = Δ P₁ + ΔP₂
ΔP₂ = -ΔP₁
negative sign indicates opposite direction.
Both are of equal magnitude.
Answer:
120°
Explanation:
Draw a free body diagram. There are three forces acting on the traffic light. Two tension forces acting along the cables, and weight.
The tension forces have an angle θ between them. That means each tension force forms an angle of θ/2 with respect to the vertical. So the y component of each tension force is:
Ty = T cos (θ/2)
Sum of the forces in the y direction:
∑F = ma
Ty + Ty − W = 0
2 Ty = W
Substituting:
2 T cos (θ/2) = W
If W = T, then:
2 W cos (θ/2) = W
2 cos (θ/2) = 1
cos (θ/2) = 1/2
θ/2 = 60°
θ = 120°
Kinetic energy = 1/2 mv²
so, you will have to do it for every single one of them if you want steps.
Kinetic Energy = For A, 202500J
For B, 90000J
For C, 168750J
For D, 75000J
From the above we an say that kinetic energy is highest in option A.
In case, there are no steps needed, just by the values we are able to understand the answer as in Option A, eventhough the mass is the same, higher the velocity or speed, higher the kinetic energy