Ya because they’re are both 50 liters
The density of silver is ρ = 10500 kg/m³ approximately.
Given:
m = 1.70 kg, the mass of silver
t = 3.0 x 10⁻⁷ m, the thickness of the sheet
Let A be the area.
Then, by definition,
m = (t*A)*ρ
Therefore
A = m/(t*ρ)
= (1.7 kg)/ [(3.0 x 10⁻⁷ m)*(10500 kg/m³)]
= 539.7 m²
Answer: 539.7 m²
Answer:

Explanation:
The original equation is:

We notice that:
- we have 1 atom of Fe on the left, and 2 atoms of Fe on the right
- we have 2 atoms of O on the left, and 3 atoms of O on the right
Therefore, the equation is not balanced.
In order to balance it, we can add:
- a coefficient 3 in front of 
- a coefficient 2 in front of 
So we have:

Now the oxygen is balanced, but the iron it not balanced yet, since we have 1 Fe on the left and 4 on the right. Therefore, we should add a coefficient 4 on the Fe on the left:

Answer
given,
vertical speed of stone,v = 12 m/s
height of the cliff = 70 m
a) time taken by the stone to reach at the bottom of the cliff
We know that,
S = u t + 1/2 a t²
- 70 = 12 t - 0.5 x 9.8 t²
4.9 t² - 12 t - 70 = 0
solving the equation
t = 5.2 s (neglecting the negative value)
b) again using equation of motion
v = u + a t
v = 12 - 9.8 x 5.2
v = -38.96 m/s
ignoring the negative sign
magnitude of velocity is equal to 38.96 m/s
c) total distance travel by the stone
vertical distance covered by the stone
v² = u² + 2 g h
0 = 12² - 2 x 9.8 x h
h = 7.34 m
to reach the stone to the same level distance travel be doubled.
Total distance travel by the stone
H = h + h + 70
H = 7.34 x 2 + 70
H = 84.7 m.
Answer:
E = 3.04 10⁻⁵ N / C
Explanation:
In this problem we can use the kinematics to find how long it takes the electron to travel the plates
Let's start by reducing the magnitudes to the SI system
vₓ = 5.35 10⁶ m / s
x = 2 cm = 2 10⁻² m
y = 1 cm = 1 10⁻² m
x = vₓ t
t = x / vₓ
t = 2 10⁻² / 5.35 10⁶
t = 3,738 10⁻⁹ s
This time is also the time it takes for vertical movement to go from the center to the plate, let's look for acceleration with Newton's second law
F = m a
a = F / m = e E / m
y =
+ ½ a t²
= 0
We replace
y = ½ e / m E t²
E = 2 y m / e t²
Let's calculate
E = 2 1 10⁻² 9.1 10⁻³¹ / (1.6 10⁻¹⁹ 3,738 10⁻⁹)
E = 18.2 10⁻³³ / 5.98 10⁻²⁸
E = 3.04 10⁻⁵ N / C