When you break a magnet in half how many poles does each piece have.

As you drive in your car at 22.5 mi/h, you see a child’s ball roll into the street ahead of you. You hit the brakes and stop as

evablogger [386]

Answer:

Explanation:

Speed of car =22.5miles/hr

U=22.5miles/hour

Applied brake and come to rest

Final velocity, =0

t, =2sec

Given that,

Speed=distance /time

Then,

Distance, =speed, ×time

Converting mile/hour to m/s

Given that

Use: 1 mile= 1600 m, 1 h= 3600s

22.5miles/hour × 1600m/mile × 1hour/3600s

Therefore, 22.5mile/hour=10m/s

Using speed =10m/s

Distance =speed ×time

Distance=10×2

Distance, =20m

The distance travelled before coming to rest is 20m.

5 0

3 years ago

A 0.300 kg potato is tied to a string with length 2.30 m , and the other end of the string is tied to a rigid support. The potat

alexdok [17]

Answer:

The speed of the potato at the lowest point is 6.714 m/s

The tension in the string is 8.82 N

Explanation:

We will use law of conservation of energy to find out the velocity

When the potato is at 2.30 m height, it will have potential energy and when the potato released it will go lowest point and it's potential energy will be convert into kinetic energy.

Potential energy = Kinetic energy

m×g×h = (1/2) m×v²

m stands for mass

g stands for gravitational constant

h stands for height

v stands for velocity

m×g×h = (1/2) m×v²

0.3×9.8×2.3 = (1/2) .3×v²

v² = 45.08

v = 6.714 m/s

The speed of the potato at lowest point is 6.714 m/s

Part B

The potato is in uniform circular motion so the acceleration is given by

a = v² / r

a stands for centripetal acceleration

According to Newton second law the acceleration is directly proportional to applied force and inversely proportional to the mass of object

So ∑ F = m × a

Two forces act on potato 1. weight due to gravitation in downward direction 2. tension in upward direction So the above equation become

Tension force - Force due to weight = m×a

T-m×g = m×a

centripetal acceleration formula =v²/r , r = l = length of the string

T = m ×(v²/l) + m×g

v = 6.714 m/s , l = 2.30 m , m = .3 kg Now put values in above equation

T = .3 × (6.714²/2.30) + .3 × 9.8

T = .3 ( 45.08/2.30) + 2.94

T = .3 (19.6) +2.94

T = 5.88 + 2.94

T = 8.82 N

The tension in the string is 8.82 N

5 0

3 years ago

A 6.0 kg box slides down an inclined plane that makes an angle of 39° with the horizontal. If the coefficient of kinetic frictio

Blababa [14]

Answer:

(B) 1.6 m/s^2

Explanation:

The equation of the forces acting on the box in the direction parallel to the slope is:

$mg sin \theta - \mu N = ma$ (1)

where

$mg sin \theta$ is the component of the weight parallel to the slope, with m = 6.0 kg being the mass of the box, g = 9.8 m/s^2 being the acceleration of gravity, $\theta=39^{\circ}$ being the angle of the incline