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inessss [21]
3 years ago
7

Predict whether each of the following molecules is polar or non-polar:a) IF,b) CS2, c) SO3, d) PCl3, e) SF6, f) IF5.

Chemistry
1 answer:
BlackZzzverrR [31]3 years ago
7 0
<h3><u>Answer;</u></h3>

Polar: IF, PCl3, IF5  

Nonpolar: CS2, SO3, SF6

<h3><u>Explanation:</u></h3>
  • Polar molecules form when two atoms do not share electrons equally in a covalent bond.
  • A molecule is classified as a polar molecule when the arrangement of the atoms is such that one end of the molecule has a positive electrical charge and the other end has a negative charge.
  • A non-polar molecule does not have electrical poles.The electrons are distributed more equally.
  • Therefore, a non-polar molecule does not have a profusion of charges at the opposite ends. The majority of hydrocarbon liquids are non-polar molecules.
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Answer:

Below:

Explanation:

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3 years ago
Devise a way to separate a mixture of sand, salt, and iron filings. Write the procedure using a step-by-step method and explain
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3 years ago
What mass of calcium chloride is needed to prepare 2.657 L of a 1.56 M solution?
inna [77]

Answer:

459.126 grams of calcium chloride is needed to prepare 2.657 L of a 1.56 M solution

Explanation:

Molarity is a measure of the concentration of a solute in a solution that indicates the amount of moles of solute that appear dissolved in one liter of the mixture. In other words, molarity is the number of moles of solute that are dissolved in a given volume.

The Molarity of a solution is determined by the following expression:

Molarity=\frac{number of moles of solute}{volume}

Molarity is expressed in units \frac{moles}{liter}

In this case:

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Replacing:

1.56 M=\frac{Number of moles of calcium chlorine}{2.657 liters}

Solving:

Number of moles of calcium chlorine= 1.56 M* 2.657 liters

Number of moles of calcium chlorine= 4.14 moles

In other side, you know:

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Then the molar mass of the calcium chloride CaCl₂ is:

CaCl₂= 40 g/mole + 2* 35.45 g/mole= 110.9 g/mole

Now it is possible to apply the following rule of three: if in 1 mole there is 110.9 g of CaCl₂, in 4.14 moles of the compound how much mass is there?

mass=\frac{4.14 moles*110.9g}{1 mole}

mass= 459.126 g

<u><em>459.126 grams of calcium chloride is needed to prepare 2.657 L of a 1.56 M solution</em></u>

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<h2><u>Answer</u> :</h2>

The most appropriate option is :

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\circ  { \underline{ \boxed{ \sf{ \color{green}{ \mathrm{hope \:  \: it \:  \: helps \:  \: you .....}}}}}}∘

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