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Otrada [13]
3 years ago
9

Which type of relationship is responsible for teaching you values and how to communicate?

Chemistry
1 answer:
Blizzard [7]3 years ago
8 0
The answer would be family.
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What example show the transformation for electrical change to radiant?
zlopas [31]
When you plug in an electrical heater, it turns the electrical energy into radiant energy.<span />
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4 years ago
Give the number of lone pairs around the central atom and the molecular geometry of XeF4.A)0 lone pairs, tetrahedralB)1 lone pai
vovangra [49]

Answer: 2 lone pairs, square planar

Explanation:

Using the VSEPR ( Valence Shell Electron Pair Repulsion)Theory

To calculate the number of lone pairs electron can be done using the formula;

Number of electrons = ½ (V+N-C+A)

V mean valency of the central atom

N means number of monovalent bonding atoms

C means charge on cation

A means charges on anion

Therefore, to calculate the number of lone pair electron C=A=0;

Number of electrons = ½ (8+4) = 12/2 = 6

Number of bonding pair = 4

Number of lone pairs of electron = 6-4 = 2

The hybridrization of the compound is sp3d2 because the number of electrons around the central atom is 6.

The geometry of the compound is square planar and this is because of the repulsion between the bonding pair of electrons and lone pair of electrons which causes the lone pair of electrons to lie in a perpendicular plane in order to acquire stability.

4 0
3 years ago
The heat capacity of water is 1cal degree'g1 (1 calorie per degree centigrade, per gram). You are given 1 gallon of water at 25
sdas [7]

Answer:

The heat needed to boil 1 gallon of water is 81,490.62 Joules.

Explanation:

Q=mc\Delta T

Where:

Q = heat absorbed or heat lost

c = specific heat of substance

m = Mass of the substance  

ΔT = change in temperature of the substance

We have :

Volume of water = V = 1 gal = 4546.09 mL

Density of water , d= 1 g/mL

mass of water = m = d × V = 1g/mL × 4546.09 mL =  4546.09 g

Specific heat of water = c = 1 Cal/g°C

ΔT = 100°C - 25°C = 75 °C

9 (boiling pint of water is 100°C)

Heat absorbed by the water to make it boil:

Q= 4546.09 g\times 1 Cal/g^oC\times 75^oC=340,956.75 Cal

1 calorie = 4.184 J

Q=\frac{340,956.75}{4.184} J = 81,490.62 J

The heat needed to boil 1 gallon of water is 81,490.62 Joules.

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3 years ago
a triangular prism with bases that are right angles measuring 5 inch by 12 inch by 13 in the height of the prism is 2 in what is
valentinak56 [21]
The answer is 1,560 hope this helps if u multiply all of it
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3 years ago
Someone help. trying to past this test but keep failing on this question.
Katarina [22]
A or b sorry if I’m wrong
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