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geniusboy [140]
3 years ago
14

Discuss FOUR ways in which one's acceptance of responsibility can influence

Chemistry
1 answer:
andrew11 [14]3 years ago
8 0

Answer:

being responsible is owing up to the possible

consequences of your decision whether it was right or wrong.

communication is a two way process in which there is a messenger and receiver

one of the ways by which a person could be responsible is by saying 'I'

in all the things he would say, instead of 'we'

for example , " We don't like the way you acted a while ago " , change it to i don't like tye way you acted a while ago.

here u r establishing ownership on the things you want to say to the person

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The 3 components of air
jok3333 [9.3K]

Nitrogen (around 78%), Oxygen (around 21%), and Argon (around 1%).

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3 years ago
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Based on the visible light spectrum, which of the following has the longest wavelength?
bezimeni [28]

Answer:

I think the answer is D a ray of violet light

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7 0
4 years ago
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What 2 things are conserved in every reaction?
Klio2033 [76]
In every reaction, mass cannot be destroyed nor created as defined by the law of conservation of mass. Energy also cannot be destroyed when a chemical reaction takes place
6 0
4 years ago
3. How many moles of silver is 8.46x1024 atoms of<br> silver?
ioda

Answer:

<h2>14.05 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L} \\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{8.46 \times  {10}^{24} }{6.02 \times  {10}^{23} }  \\  = 14.053156

We have the final answer as

<h3>14.05 moles</h3>

Hope this helps you

6 0
2 years ago
What is the correct name of this compound?
Reika [66]

Answer:

7. 3–ethyl–6 –methyldecane

8. 5–ethyl–2,2–dimethyl–4–propyl–4 –heptene

Explanation:

It is important to note that when naming organic compounds having two or more different substituent groups, we simply name them alphabetically.

The name of the compound given in the question above can be written as follow:

7. Obtaining the name of the compound.

Compound contains:

I. Decane.

II. 3–ethyl.

III. 6 –methyl.

Naming alphabetically, we have

3–ethyl–6 –methyldecane

8. Obtaining the name of the compound.

Compound contains:

I. 2,2–dimethyl.

II. 4–propyl.

III. 4 –heptene.

IV. 5–ethyl.

Naming alphabetically, we have

5–ethyl–2,2–dimethyl–4–propyl–4 –heptene

8 0
3 years ago
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