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Greeley [361]
3 years ago
8

significant figures are digits read directly from measuring instrument plus one more digit, which is ______ by the observer

Physics
2 answers:
Kay [80]3 years ago
6 0
Estimated by the observer.

Take a buret, you can read to the 0.1 mL directly from the device, but the amount may lie between the 0.1 marks so you can estimate how far between the marks the fluid lies.
melisa1 [442]3 years ago
4 0

Significant figures are digits are read directly from the measuring instrument plus  one more digit which is <u>Estimated </u> by the observer.

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How much energy in Joules (J) would an electric heater that draws 9.5 A when connected to a 120 V supply use if the heater were
leonid [27]
<h2>Energy used by heater is 8.21 x 10⁶ J</h2>

Explanation:

Energy = Power x Time

Power = Voltage x Current

Voltage = 120 V

Current = 9.5 A

Power = Voltage x Current

Power = 120 x 9.5 = 1140 W

Time = 2 hours = 2 x 60 x 60 = 7200 s

Energy = Power x Time

Energy = 1140 x 7200

Energy = 8208000 J

Energy used by heater is 8.21 x 10⁶ J

7 0
4 years ago
1. Summarize What are the four conditions of a<br>purely competitive market?​
bearhunter [10]

Answer:

Explanation:

1. Many buyers and sellers participate in the market.

2. Sellers offer identical products.

3. Buyers and sellers are well informed about products.

4. Sellers are able to enter and exit the market freely.

5 0
3 years ago
What are two ways that magnetism is created? Use evidence from the text to<br> support your answer.
pav-90 [236]

As Ampere suggested, a magnetic field is produced whenever an electrical charge is in motion. The spinning and orbiting of the nucleus of an atom produces a magnetic field as does electrical current flowing through a wire. The direction of the spin and orbit determine the direction of the magnetic field.

8 0
3 years ago
4. Determine the net force for the free-body
krek1111 [17]

Answer:

Fapp =44N is the correct answer

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3 years ago
At a distance of 0.208 cm from the center of a charged conducting sphere with radius 0.100cm, the electric field is 485 n/c . wh
Anna35 [415]

We have the equation for electric field E = kQ/d^{2}

Where k is a constant, Q is the charge of source and d is the distance from center.

In this case E is inversely proportional to d^{2}

So, \frac{E_{1} }{E_{2}} = \frac{d_{2}^{2}}{d_{1}^{2}}

E_{1} = 485 N/C

d_{1} = 0.208 cm

d_{2} = 0.620 cm

E_{2} = ?

\frac{485 }{E_{2}} = \frac{0.620^{2}}{0.208^{2}}

E_{2} = \frac{485*0.208^{2}}{0.628^{2}}

E_{2} = 53.20 N/C

7 0
3 years ago
Read 2 more answers
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