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4 years ago

What information in the MSDS would be most important to know at the end of an experiment?

1 answer:

8 0

The most important information in the MSDS that is useful at the end of an experiment is how to manage or dispose of the waste materials of the experiment. This is important especially if the materials used are toxic. They cannot just be disposed in the sink or the trash bin. They must be disposed in a waste bottle or other methods.

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How do you calculate the following:<br> Final Velocity?<br> Acceleration?<br> and Force?

kicyunya [14]

Wait like the equations, or is there an actual question?

Equations are

Final velocity (Vf) = Initial velocity (Vi) + Acceleration (a) x Time (t)
Acceleration (a) = (Final velocity [Vf] - initial velocity [Vi]) divided by Time (t)
Force (f) = Mass (m) x Acceleration (a)

(Short version)

Vf = Vi + a(t)
a = (Vf - Vi) divided by t
F = m x a

6 0

4 years ago

Read 2 more answers

Help with 1 2 and 3 please

geniusboy [140]

1. Amperes, is the SI unit (also a fundamental unit) responsible for current.

2. $I = \frac{q}{t}$ Δq over Δt technically

Rearrange for Δq

I x Δt = Δq

1.5mA x 5 = Δq

Δq = 0.0075

Divide this by the fundamental charge "e"

Electrons: 0.0075 / 1.60 x 10^-19

Electrons: 4.6875 x 10^16 or 4.7 x 10^16

3. So we know that the end resistances will be equal so:

ρ = RA/L

ρL = RA

ρL/A = R

Now we can set up two equations one for the resistance of the aluminum bar and one for the copper: Where 1 represents aluminum and 2 represents copper

$\frac{p1L1}{A1} = \frac{p2L2}{A2}\\$

We are looking for L2 so we can isolate using algebra to get:

$\frac{A2(\frac{P1L1}{A1}) }{P2} = L2$

If you fill in those values you get 0.0205

or 2.05 cm

6 0

4 years ago

What would happen to Earth if ocean floor were created at divergent boundaries at a faster rate than it is destroyed at converge

saveliy_v [14]

Answer:

The Earth would increase in volume.

Explanation:

Earth's crust is less dense than the mantle.

PLZ mark brainliest

4 0

3 years ago

What is the magnetic field strength at point 1 in the figure? (figure 1)

Lana71 [14]

The magnetic field strength at point 1 in the figure will be 6.67 ×10⁻⁵ T.

<h3>What is magnetic field strength?</h3>

The number of magnetic flux lines on a unit area passing perpendicular to the given line direction is known as induced magnetic field strength .it is denoted by B.

The magnetic field strength is found as;

$B = \frac{\mu_0I}{2r} \\\\ \mu_0 = 4 \PI \times 10^{-7}$

In the formula,I denote current, and r denotes the distance between the point and the current carrying wire and magnetic field due to current in the bottom wire.

At point 1, the net magnetic field is found as the sum of magnetic field due to current in the top wire.

$\rm B_{net} = B1_+(-B_2)$

$B = \frac{ 4 \PI \times 10^{-7}I}{2r} \\\\ \rm B_{net} = B_1_+(-B_2)\\\\ \rm B_{net} = \frac{4 \times \pi \times 10^{-7} \times 10}{2 \times \pi \times 0.02} -\frac{4 \times \pi \times 10^{-7} \times 10 }{2 \times \pi \times 0.06} \\\\\ \rm B_{net} = 6.67 \times 10^{-5} T$

Hence, the magnetic field strength at point 1 in the figure will be 6.67 ×10⁻⁵ T.

To learn more about the strength of induced magnetic field, refer:

brainly.com/question/2248956

#SPJ4

6 0

2 years ago

A block of aluminum occupies a volume of 15.0 ml and weighs 40.5 what is its density

AVprozaik [17]

D = 40.5 g / 15.0 mL<span>d = 2.70 g/mL</span>

5 0

3 years ago

Read 2 more answers