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Roman55 [17]
3 years ago
7

Pretty pretty please if ur good at geometry!! Help a girl out!!

Mathematics
1 answer:
sweet-ann [11.9K]3 years ago
4 0

Answer:

Yes, They are similar by SSS PMK similar to LMQ.

Step-by-step explanation:

Similar triangles corresponding side lengths are in a proportion.

KM corresponds with MQ

PM corresponds with LM.

Set up this proportion.

\frac{km}{pm}  =   \frac{lm}{mq}

\frac{15}{28}  =  \frac{21}{39.2}

Cross multiply

588 = 588

So the triangles ARE Similar.

  • PM corresponds with LM
  • KM corresponds with MQ
  • PK corresponds with LQ
  • So PMK is similar to LMQ
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What is the probability of first drawing a red card, then a face card, and then a black card? Do not round your intermediate com
lozanna [386]

Answer:

 [ 26 / 425 ] ≈ 0.0612

Step-by-step explanation:

Solution:-

- First we will describe the standard deck of 52 cards in terms of black, red and face cards found in a standard deck

- Following is a table of distribution of colored and face card found in a standard deck:

                 Type                   Number of cards

                 1 - 10                                40

                 Black                               26

                 Red                                 26

                 Face                                12

- The numerical cards from digit ( 1 to 10 ) are found in all 4 suits ( Clubs, Diamonds, Spades, and Hearts ). Hence, 10 x 4 = 40

- The entire deck is split in two colors ( Red and Black ) equally. So, the number of Black and Red cards are = 52 / 2 = 26 cards.

- The face cards are of three types ( King, Queen and Jack ). These three face cards are found in each of the 4 suits. Hence, Total number of face cards are = 4 * 3 = 12

- We will now consider the probabilities asscociated with each type. We will define 3 events and write down their proability as expressed:

Event ( A ): First draw is a red card.

- The probability of this event can be determined with the help of the table given above. There are a total of 26 red card in a standard deck of 52 cards. Hence,

            p ( A ) = [ Number of red cards ] / [ Total cards in a deck ]

            p ( A ) = [ 26 ] / [ 52 ]

            p ( A ) = 1 / 2

- After we make the first draw of a red card. Our deck distribution is changed to Number of Red cards remaining = 25 and total deck now has 51 cards remaining.

- We will define the next event as:

Event ( B ): The second draw is a face card.

- The probability of this event can be determined with the help of the table given above. There are a total of 12 face cards in a standard deck of 52 cards which is now down to 51 cards. Hence,

            p ( B ) = [ Number of face cards ] / [ Total cards in a deck ]

            p ( B ) = [ 12 ] / [ 51 ]

            p ( B ) = 4 / 17

- After we make the first draw of a face card. Our deck distribution is changed to Number of Face cards remaining = 11 and total deck now has 50 cards remaining.

- We will define the next event as:

Event ( C ): The third draw is a black card.

- The probability of this event can be determined with the help of the table given above. There are a total of 26 black cards in the deck. The total number of cards are down to 50 cards only. Therefore,

            p ( C ) = [ Number of black cards ] / [ Total cards in a deck ]

            p ( C ) = [ 26 ] / [ 50 ]

            p ( C ) = 13 / 25

- The entire drawing process consists of 3 events which are dependent on each draw. However, for the overall event to occur i.e drawing a red card , then a face card, and then a black card. We will multiply all three outcomes as follows:

          p ( T ) = p ( A ) * p ( B ) * p ( C )

          p ( T ) = [ 1 / 2 ] * [ 4 / 17 ] * [ 13 / 25 ]

          p ( T ) =  [ 26 / 425 ] ≈ 0.0612

4 0
3 years ago
Which graph shows solution to which inequality
Rudik [331]

Answer:

I don’t see a graph

Step-by-step explanation:

5 0
3 years ago
Find the simplified product 2 sqrt 5x^3 ( -3 sqrt 10x^2)
Ksivusya [100]

Answer:

-30x^2 sqr2x

Step-by-step explanation:

7 0
3 years ago
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A square has side length of 9 in. If the area is doubled, what happens to the side length?
Alika [10]

Answer:

The side length is multiplied by \sqrt{2}

Step-by-step explanation:

we know that

The area of the original square is equal to

A=9^{2}=81\ in^{2}

If the area is doubled

then

The area of the larger square is

A1=(2)81=162\ in^{2}

Remember that

If two figures are similar, then the ratio of its areas is equal to the scale factor squared

Let

z ----> the scale factor

x ----> the area of the larger square

y ---> the area of the original square

so

z^{2}=\frac{x}{y}

we have

x=162\ in\^{2}

y=81\ in\^{2}

z^{2}=\frac{162}{81}

z^{2}=2

z=\sqrt{2} ------> scale factor

therefore

The side length is multiplied by \sqrt{2}

7 0
3 years ago
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