Answer: AA similarity theorem.
Step-by-step explanation:
Given : AB ∥ DE
Prove: ΔACB ≈ ΔDCE
We are given AB ∥ DE. Because the lines are parallel and segment CB crosses both lines, we can consider segment CB a transversal of the parallel lines. Angles CED and CBA are corresponding angles of transversal CB and are therefore congruent, so ∠CED ≅ ∠CBA.
Also ∠C ≅ ∠C using the reflexive property.
Therefore by AA similarity theorem , ΔACB ≈ ΔDCE
- AA similarity theorem says that if in two triangles the two pairs of corresponding angles are congruent then the triangles are similar .
Answer: A
The y-intercept is 3, not -3, so answer C is eliminated
Choose a point that is clearly in the shaded area or one that is clearly in the unshaded region
I choose the point (0, 0) and substituted these values in the equation and since 0 < 3, A is the correct answer
Answer:
Step-by-step explanation:2x + 9x - 9 = 16x + 16 - 5
= 11x - 9 = 16x + 11
11x - 16x = 11 + 9
5x = 20
x = 20/5
x = 4
Plz mark it as brainliest:)
Answer:
The last one
Step-by-step explanation:
Ypu would subtract Y from the other points Y
Then you would subtract X from the ither points X.
Then you would put the Y value over the X
Then simiplify
