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miss Akunina [59]
4 years ago
13

A car traveling 92 km/h is 130 m behind a truck traveling 75 km/h. how long will it take the car to reach the truck?

Physics
1 answer:
Rufina [12.5K]4 years ago
7 0
SOLUTION: A car traveling<span> 88 </span>km/hr<span> is 110 </span>m behind<span> a </span>truck traveling 75 km/hr<span>. How </span>long will<span> it </span>take<span>the </span>car<span> to </span>reach<span> the </span>truck<span>? Algebra -> Customizable Word ...</span>
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What is it called cavity left behind in the rock after an organism's hard part has dissolved.
Lapatulllka [165]

Mold

Explanation:

A mold is a cavity that is left behind in the rock after an organism hard part has been dissolved. These are important fossils that useful in relative dating.

  • Some hard parts of organism are preserved in form of molds in soft sediments.
  • The outline and important details of the hard part is preserved when the mold dissolves away.
  • Fossil molds are representative on the internal outline of the hard parts of organisms.
  • They are usually recognized as a part of body fossil in a section.

learn more:

Fossils brainly.com/question/7382392

#learnwithBrainly

5 0
3 years ago
Kind of mixture that has the same mixture throughout
Ainat [17]
It's a homogeneous mixture
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8 0
3 years ago
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For copper, ρ = 8.93 g/cm3 and M = 63.5 g/mol. Assuming one free electron per copper atom, what is the drift velocity of electro
viktelen [127]

Answer:

V_d = 1.75 × 10⁻⁴ m/s

Explanation:

Given:

Density of copper, ρ = 8.93 g/cm³

mass, M = 63.5 g/mol

Radius of wire = 0.625 mm

Current, I = 3A

Area of the wire, A = \frac{\pi d^2}{4} = A = \frac{\pi 0.625^2}{4}

Now,

The current density, J is given as

J=\frac{I}{A}=\frac{3}{ \frac{\pi 0.625^2}{4}}= 2444619.925 A/mm²

now, the electron density, n = \frac{\rho}{M}N_A

where,

N_A=Avogadro's Number

n = \frac{8.93}{63.5}(6.2\times 10^{23})=8.719\times 10^{28}\ electrons/m^3

Now,

the drift velocity, V_d

V_d=\frac{J}{ne}

where,

e = charge on electron = 1.6 × 10⁻¹⁹ C

thus,

V_d=\frac{2444619.925}{8.719\times 10^{28}\times (1.6\times 10^{-19})e} = 1.75 × 10⁻⁴ m/s

4 0
3 years ago
Read 2 more answers
4. A substance has a density of 0.79 g/cm'. It is soluble in water. List all the possibilities of what it might be How could you
Natasha_Volkova [10]

Answer:

See explanation

Explanation:

Given that the density of the unknown substance is 0.79 g/cm3 and is soluble in water, the possible substances it could be are;

i) t-butanol

ii) ethanol

iii) 2-propanol

iv) acetone

However, the actual identity of the unknown substance can be obtained by carrying out a boiling point test. The four substances listed above have different boiling points. Hence the boiling point of the unknown substance ultimately discloses its identity.

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3 years ago
What is the role of the sun in the formation of clouds??
klasskru [66]
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3 years ago
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