Decantation
Centrifugation
Filtration
Evaporation
<h3><u>Answer;</u></h3>
3p34s23d7
<h3><u>Explanation</u>;</h3>
- Electrons in an atom are contained in specific energy levels that are different distances from the nucleus.
- Within each energy level is a volume of space where specific electrons are likely to be located, called orbitals. Orbitals are of different shapes, denoted by a letter (s, p, d, f, g).
- S-orbital takes a maximum of two electrons, p-orbital take a maximum of six electrons, d-orbital takes a maximum of 10 electrons, and so fourth.
- The electron filling pattern takes; 1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p.........
- Therefore; in this case after 3p3, we then go to 4s, with 2 electrons, then 3d which takes 7 electrons.
Answer:
pKa of the acid HA with given equilibrium concentrations is 6.8
Explanation:
The dissolution reaction is:
HA ⇔ H⁺ + A⁻
So at equilibrium, Ka is calculated as below
Ka = [H⁺] x [A⁻] / [HA] = 2.00 x 10⁻⁴ x 2.00 x 10⁻⁴ / 0.260
= 15.38 x 10⁻⁸
Hence, by definition,
pKa = -log(Ka) = - log(15.38 x 10⁻⁸) = 6.813
Answer:
2K + 2H2O → H2 + 2KOH
Explanation:
Find how many atoms you have on both sides then add 2 to both sides.
Reactant: Products:
K: 1+1=2 K: 1+1=2
H: 2+2=4 H: 3+1=4
O: 1+1=2 O: 1+1=2
Therefore it is balanced. Hope this helps
Answer:
4180J
Explanation:
(25.0g)(4.184J/g°C)(75°C-35.0°C)
(25.0g)(40.0°C)(4.184J/g°C)
(1.00*10³g°C)(4.184J/g°C) = 4184J
use sig figs:
4180J
