seaweed having 50 g salt in 1 L water. The bucket contains 150 g of salt in 2 L of water
amount of water present in bucket is twice to amount of water in weed

At equilibrium, volume of water in weed is x and volume in bucket is y but concentration remain same as follows:

At equilibrium, weed loose z L from 1 L water to bucket containing 2 L as follows:

Thus, Weed will loose 0.25 L of water
Quarts of pure antifreeze must be added to 5 quarts of a 20 antifreeze solution to obtain a 50 antifreeze solution is 3.
Antifreeze solution is a solute that lowers the freezing point of the liquid in a solution.
For calculating the amount of quarts of pure antifreeze solution added can be given by:
5×20/100 + x × 100% = (x+5) × 50/100
Where, x is the amount of antifreeze required for addition and pure antifreeze is 100% of the antifreeze taken.
1 + x = (x+5) 0.5
1 + x = 0.5x + 2.5
0.5x = 1.5
x = 3
So, 3 quarts of pure antifreeze must be added to 5 quarts of a 20 antifreeze solution to obtain a 50 antifreeze solution.
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Answer: The chemical formula of this precipitate is
.
Explanation:
An equation which depicts the chemical reaction of substances in the form of chemical formulas is called a chemical equation.
For example, chemical equation for an aqueous solution of sodium phosphate
and an aqueous solution of magnesium sulfate
are mixed, a precipitate forms is as follows.

Here, trimagnesium phosphate is the precipitate. The chemical formula of this precipitate is
.
Thus, we can conclude that the chemical formula of this precipitate is
.
Ca(OH)2
Make sure your charges are balanced when you write the compound. Ca has a +2 charge and OH has a -1 charge so you need 2 of OH.