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allsm [11]
2 years ago
9

Every five years in August, the population of a certain city is recorded. In 2010, the city had a population

Mathematics
1 answer:
Ipatiy [6.2K]2 years ago
3 0

Answer:

10,000

Step-by-step explanation:

yes

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13. En un pueblo, 5 personas escucharon una noticia. En una hora, cada una de ellas
Vera_Pavlovna [14]

Answer:

En 5 horas se habrá enterado todo el pueblo.

Step-by-step explanation:

Sabemos que en un pueblo 5 personas escucharon una noticia.

Una hora más tarde, cada una de ellas le contó la noticia a otras 5.

Luego, éstas contaron la noticia a otras 5 y así sucesivamente.

Nadie cuenta ni escucha la noticia más de una vez y en ese pueblo hay un poco más de 19000 habitantes.

La ecuación a desarrollar para resolver el problema es la siguiente :

Comenzamos con 5 personas que escucharon la noticia a la ''hora 0''.

Una hora más tarde, cada una de ellas le contó a 5 personas, es decir , pasada la primera hora tendremos :

5+5^{2}=30 (I)

Las 5 personas originales de la ''hora 0'' más 25 personas que se enteraron pasada la primera hora. La ecuación que planteamos es la siguiente :

5^{1}+5^{2}+5^{3}+...+5^{x}>19000 (II)

Buscamos el valor de x que satisface la ecuación (II).

Probando y realizando las sumas encontramos que :

5^{1}+5^{2}+5^{3}+5^{4}+5^{5}+5^{6}>19000

19530>19000

El valor de x que satisface (II) es x=6.

Para hallar el número de horas nos fijamos que en (I) el valor del mayor exponente del 5 es el número 2. Para ese valor 2, el tiempo que pasó es una hora.

Entonces para nuestro x=6, el número de horas que pasaron son 5 horas (1 menos que el valor de x)

Todo el pueblo se habrá enterado en 5 horas de la noticia.

7 0
3 years ago
PLEASE HELP I WILL REWARD BRANLIEST AND 99 POINTS!!!!
ch4aika [34]

Answer:

Step 3, because the solution should also include all the values for x between the two given values

Step-by-step explanation:

step 1

we have

y_1=\left|x-4\right|

y2=1

step 2

The graph in the given problem

step 3

Identify the solution when y1\leq y2

so

\left|x-4\right|\le1

using a graphing tool

The solution is the interval  -----> [3,5]

see the attached figure

All real numbers greater than or equal to 3 and less than or equal to 5

therefore

The first step in which the student made an error is step 3

6 0
3 years ago
Read 2 more answers
What is the answer please hurry this is to pass my class 10 points!!!
-BARSIC- [3]

Answer:

The answer is A I suppose

7 0
3 years ago
HELPS PLS 44 and 17 what is y and x
olga_2 [115]
Y is 11.82
i put my working below

3 0
3 years ago
i need help asap please dont type random anwsers, that will result in it being deleted. GIVING BRAINLIEST ONLY TO CORRECT, INCOR
Veseljchak [2.6K]

Answer:

The area of the rectangle <em>TOUR</em> is 80.00 unit².

Step-by-step explanation:

The area of a rectangle is computed using the formula:

Area\ of\ a\ Rectangle=length\times width

Since the dimensions of the rectangle are not provided we can compute the dimensions using the distance formula for two points.

The distance formula using the two point is:

distance=\sqrt{(x_{2}-x_{1})^{2}+(y_{2}-y_{1})^{2}}

Considering the rectangle <em>TOUR</em> the area formula will be:

Area of Rectangle <em>TOUR</em> = <em>TO × OU</em>

The co-ordinates of the four vertices of a triangle are:

T = (-8, 0), O = (4, 4), U = (6, -2) and R = (-6, -6)

Compute the distance between the vertices <em>T</em> and <em>O</em> as:

TO=\sqrt{(4-(-8))^{2}+(4-0)^{2}}\\=\sqrt{12^{2}+4^{2}} \\=\sqrt{160} \\=4\sqrt{10}

Compute the distance between the vertices <em>O </em>and <em>U</em> as:

OU=\sqrt{(6-4)^{2}+(-2-4)^{2}}\\=\sqrt{2^{2}+6^{2}} \\=\sqrt{40} \\=2\sqrt{10}

Compute the area of rectangle TOUR as follows:

Area\ of\ TOUR=TO\times OU\\=4\sqrt{10}\times 2\sqrt{10}\\=80\\\approx80.00 unit^{2}

Thus, the area of the rectangle <em>TOUR</em> is 80.00 unit².

6 0
3 years ago
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