Every five years in August, the population of a certain city is recorded. In 2010, the city had a population

How to find the volume of a quarter-sphere?

Ganezh [65]

As the word suggests, a quarter-sphere is a quarter of a sphere, and thus the volume of a quarter-sphere is a quarter of the volume of the sphere.

The volume of a sphere is computed as

$\dfrac{4}{3} \pi r^3$

So, the volume of a quarter-sphere is

$\dfrac{1}{4}\cdot \dfrac{4}{3} \pi r^3 = \dfrac{1}{3} \pi r^3$

7 0

3 years ago

Jennifer made 5 Liters of punch for her party. Her brother made another 750 milliliters if they combine the two batches how many

tia_tia [17]

Answer:

Step-by-step explanation:

The total amount of punch that Jennifer made for her party is 5 Liters. Her brother made another 750 milliliters.

1000 milliliters = 1 liter

750 milliliters = 750/1000 = 0.75Liter

if they combine the two batches, the total amount made would be

5 + 0.75 = 5.75Liter

= 5.75 × 1000 = 5750 milliliters

The number of 180 milliliters servings would be

5750/180 = 31 servings

There would be leftovers of 170 milliliters

7 0

3 years ago

someone please explain to me how to find the area PLEASE! Find the area and perimeter of quadrilateral ABCD below. Explain your

Lunna [17]

Answer:

Part A) The area of the figure is $24\ units^{2}$

Part B) The perimeter of the figure is $20\ units$

Step-by-step explanation:

step 1

Find the area of the figure

we know that

The area of the figure is equal to the area of triangle ABD plus the area of triangle BCD

The area of triangle is equal to

$A=\frac{1}{2}bh$

<u>Area of triangle ABD</u>

Observing the graph

$b=BD=(-2+8)=6\ units$

$h=(9-5)=4\ units$

substitute

$A=\frac{1}{2}(6)(4)=12\ units^{2}$

<u>Area of triangle BCD</u>

Observing the graph

$b=BD=(-2+8)=6\ units$

$h=(5-1)=4\ units$

substitute

$A=\frac{1}{2}(6)(4)=12\ units^{2}$

The area of the figure is

$12\ units^{2}+12\ units^{2}=24\ units^{2}$

step 2

Find the perimeter of the figure

we know that

The perimeter of the figure is equal to

$P=AB+BC+CD+AD$

we have

$A(-5,1),B(-8,5),C(-5,9),D(-2,5)$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Find the distance AB

$d=\sqrt{(5-1)^{2}+(-8+5)^{2}}=5\ units$

Find the distance BC

$d=\sqrt{(9-5)^{2}+(-5+8)^{2}}=5\ units$

Find the distance CD

$d=\sqrt{(5-9)^{2}+(-2+5)^{2}}=5\ units$

Find the distance AD

$d=\sqrt{(5-1)^{2}+(-2+5)^{2}}=5\ units$

substitute the values

$P=5+5+5+5=20\ units$

7 0

3 years ago

in parallelogram JKLM, the ratio of the measure of angle J to the measure of angle M is 5:4. Find the measurement of angle J and

Helga [31]

Since we know that these two are consecutive angles and consecutive angles add up to 180 deg, we can come up with the equation 4x +5x =180. Solving this out shows us that x = 20 and the measure of angle J is 100 deg while the measure of angle M is 80 deg.

5 0

3 years ago

A rectangular paperboard measuring 29in long and 20in wide has a semicircle cut out of it, as shown below.

katen-ka-za [31]

Here, we are required to find the area of the paper board given after the semicircle is cut out of it

Area of the paper board thatremains is 423 in²

Length = 29 in

Width = 20 in

Area of a rectangle = length × width

= 29 in × 20 in

= 580 in²

Area of a semi circle = πr²/2

π = 3.14

r = diameter / 2 = 20 in / 2 = 10 in

Area of a semi circle = πr²/2

= 3.14 × (10 in)² / 2

= 3.14 × 100 in² / 2

= 314 in²/2

= 157 in²

The semicircle is cut out of the rectangle

Find the area of the paper board that remains after the semicircle is cut out of it by subtracting the area of a semi circle from the area of a rectangle

Area of the paper board that remains = Area of a rectangle - Area of a semi circle

= 580 in² - 157 in²

= 423 in²

brainly.com/question/16994941

6 0

3 years ago