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Paha777 [63]
3 years ago
10

Show that (A | B) U (B \ A) = (AUB) \(B n A).

Mathematics
1 answer:
trasher [3.6K]3 years ago
7 0

Answer:

We have to prove,

(A \ B) ∪ ( B \ A ) = (A U B) \ (B ∩ A).

Suppose,

x ∈ (A \ B) ∪ ( B \ A ), where x is an arbitrary,

⇒ x ∈ A \ B or x ∈ B \ A

⇒ x ∈ A and x ∉ B or x ∈ B and x ∉ A

⇒  x ∈ A or x ∈ B and x ∉ B and x ∉ A

⇒ x ∈ A ∪ B and x ∉ B ∩ A

⇒ x ∈ ( A ∪ B ) \ ( B ∩ A )

Conversely,

Suppose,

y ∈ ( A ∪ B ) \ ( B ∩ A ), where, y is an arbitrary.

⇒ y ∈ A ∪ B and x ∉ B ∩ A

⇒ y ∈ A or y ∈ B and y ∉ B or y ∉ A

⇒  y ∈ A and y ∉ B or y ∈ B and y ∉ A

⇒  y ∈ A \ B  or  y ∈ B \ A

⇒  y ∈ ( A \ B ) ∪ ( B \ A )

Hence, proved......

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\frac{3}{2}

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\frac{1}{2} ÷ \frac{1}{3}

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Today joelle walked at a rate of 3 miles per hour and she ran 15 minutes at a rate of 6 miles per hour.How many total miles did
svetoff [14.1K]
I added a screenshot with the complete question

<u><em>Answer:</em></u>
Total miles = 2.5 miles

<u><em>Explanation:</em></u>
<u>1- While walking:</u>
We are given that Joelle walked 20 minutes at a rate of 3 miles per hour.
This means that she walked \frac{20}{60} =  \frac{1}{3} of an hour at a rate of 3 miles per hour
The formula that relates distance, time and velocity is:
Distance = velocity * time
<u>Substitute with the givens to get the distance she covered while walking:</u>
Distance = 3 * \frac{1}{3} = 1 mile

<u>2- While running:</u>
We are given that Joelle ran 15 minutes at a rate of 6 miles per hour
This means that she ran \frac{15}{60} =  \frac{1}{4} of an hour at a rate of 6 miles per hour
The formula that relates distance, time and velocity is:
Distance = velocity * time
<u>Substitute with the givens to get the distance she covered while running:</u>
Distance = 6 * \frac{1}{4} = 1.5 miles

<u>3- getting the total mileage:</u>
Total distance she covered = distance while walking + distance while running
Total distance she covered = 1 + 1.5
Total distance she covered = 2.5 miles

Hope this helps :)

4 0
3 years ago
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