Take the logarithm of both sides. The base of the logarithm doesn't matter.
Drop the exponents:
Expand the right side:
Move the terms containing <em>x</em> to the left side and factor out <em>x</em> :
Solve for <em>x</em> by dividing boths ides by 5 log(4) - log(3) :
You can stop there, or continue simplifying the solution by using properties of logarithms:
You can condense the solution further using the change-of-base identity,
The answer is 10.24695. Which is 10.2 for you!
Hi there!
Many things we do in everyday life have a variety of ways we can go about accomplishing them, but we most often choose the most practical and efficient method.
Efficiency saves time and prevents over-complication, which may lead to errors.
We might need to identify the specifics of the task and its circumstances to be able to determine the most efficient method to do it.
Solving a quadratic equation, we also must think about the most efficient method that can lead us to the correct answer. And doing so, we must identify the circumstances of the equation; Can it be solved by factoring? Is it easy to factor? What form is this quadratic equation in?
For example, let's say we're given the equation (x-1)(x+2)=0. This is an equation in factored form. In these kinds of scenarios, we can <em>easily</em> solve by setting each term equal to 0 (the Zero Product Property). This is the <em>most efficient </em>method:
x-1=0 --> x=1
x+2=0 --> x=-2
I hope this helps!
The answer is: x = 10, y = 2
Leave a thanks because your welcome :)
Work:
x + y = 12
(10) + (2)+ = 12
Correct
x - 2y = 6
(10) - 2(2) = 6
10 - 4 = 6
Correct
