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3 years ago

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The electric flux through a square-shaped area of side 5 cm near a large charged sheet is found to be 3 × 10−5 N · m2 /C when th

e area is parallel to the plate. Find the charge density on the sheet.

1 answer:

Zanzabum3 years ago

5 0

Answer:

$\sigma=2.124\times 10^{-13}C/m^{2}$

Explanation:

Given:

Electric Flux = $3\times10^{-5}N.m^2/C$

Side of sheet = 5cm

Area of the square sheet, A= 5×5 = 25cm²=25×10⁻⁴ m²

Now

the electric flux (Φ) is given as:

$\phi =EA$

where, E = Electric field

or

$E=\frac{\phi}{A}$

substituting the values in the above equation, we get

$E=\frac{3\times10^{-5}N.m^2/C}{25\times 10^{-4}}$

$E=0.012N/C$

Now the charge density (σ) on a sheet is given as:

$\sigma=2\epsilon_oE$

where, $\epsilon_o$ = Permittivity of the free space = 8.85×10⁻¹²

substituting the values in the above equation, we get

$\sigma=2\times 8.85\times10^{-12}\times 0.012$

$\sigma=2.124\times 10^{-13}C/m^{2}$

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4 years ago

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Answer:

Efficiency = 52%

Explanation:

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