Answer:
The funda mental frequency of the original tube is 182Hz.
Explanation:
See the attachment for the calculation steps.
In order to calculate the fundamental frequency of the original closed tube we need to find the length of the tube which is equal to the sum of the lengths of the two new tubes.
For closed tubes
f = nv/4L (n = 1, 3, 5,...n)
f = nv/2L (n = 1, 2, 3,...n)
The details of calculation can be found below in the attachment.
We shall consider two properties:
1. Temperature difference
2. Thermal conductivity of the material
Use a cylindrical rod of a given material (say steel) which is insulated around its circumference.
One end of the rod is dipped in a large reservoir of water at 100 deg.C and the other end is dipped in water (with known volume) at 40 deg. C. The cold water if stored in a cylinder which is insulated on all sides. A thermometer reads the temperature of the cold water as a function of time.
This experiment will show that
(a) heat flows from a region of high temperature to a region of lower temperature.
(b) The thermal energy of a body increases when heat is added to it, and its temperature will rise.
(c) The thermal conductivity of water determines how quickly its temperature will rise. If mercury replaces water in the cold cylinder, its temperature will rise at a different rate because its thermal conductivity is different.
Answer:
The current decreases.
Explanation:
Current and resistance are inversely proportional. The equation connecting current, resistance and voltage is 
, where V is voltage, I is current and R is resistance.
Rearranging this equation, you get:
and
If the value of voltage in both equations remains constant, and the value of R decreases, the value of I will increase. Conversely, if in the second equation , the value of V remains constant the value of I decreases, then the value of R, resistance will increase.
Thus, it can be seen that the current will decrease as resistance increases and vice versa.
Wave A would have higher amplitude
Hope this helps :D
