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fredd [130]
3 years ago
10

PLEASE HELP!!!! WILL MARK BRAINLIEST

Chemistry
1 answer:
11111nata11111 [884]3 years ago
5 0

This is sulfer, sulfer is the atom with 16 protons, neutrons and electrons.

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Describe any evidence that a chemical reaction occurred when you added 6 m hcl to the solution of sodium acetylsalicylate, also
irina1246 [14]

The evidence that a chemical reaction occurred is can be change in color , formation of a precipitate , Here in the case when 6 m HCl to the solution of sodium acetylsalicylate, the formation of precipitate that is of aspirin takes places that can be taken as a evidence that a reaction is occured. The reaction can be seen in the image attached.

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3 years ago
How is Waste Management playing a role in ENERGY conservation?
bagirrra123 [75]

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Proper waste management allows for separation at the source and subsequent recycling, which allows materials that required energy and raw materials to be reincorporated into the production cycle, as the finished material is incorporated back into the production cycle, the amount of energy required for the production of <u>the final product is less than if it were made from the start</u>.

Explanation:

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8 0
3 years ago
Please help me! I'm having trouble!
otez555 [7]
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4 0
3 years ago
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6. The drawing shows Samir riding his mountain bike.
ElenaW [278]

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Explanation:

4 0
3 years ago
Anyone? Please help
snow_tiger [21]

Answer:

The limiting reacting is O2

Explanation:

Step 1: data given

Number of moles O2 = 21 moles

Number of moles C6H6O = 4.0 moles

Step 2: The balanced equation

C6H6O + 7O2 → 6CO2 + 3H2O

Step 3: Calculate the limiting reactant

For 1 mol C6H6O we need 7 moles O2 to produce 6 moles CO2 and 3 moles H2O

O2 is the limiting reactant. It will completely be consumed (21 moles).

C6H6O is in excess.

For 7 moles O2 we need 1 mol C6H6O

For 21 moles O2 we'll need 21/7 = 3 moles C6H6O

There will remain 4.0 - 3.0 = 1 mol C6H6O

Step 4: calculate products

For 1 mol C6H6O we need 7 moles O2 to produce 6 moles CO2 and 3 moles H2O

For 21 moles O2 we'll have 6/7 * 21 = 18 moles CO2

For 21 moles O2 we'll have 3/7 * 21 = 9 moles H2O

The limiting reacting is O2

7 0
4 years ago
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