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VladimirAG [237]
3 years ago
10

Which states of matter have particles that move independently of one another with very little attraction?

Chemistry
2 answers:
maks197457 [2]3 years ago
8 0
Gas -- move very independently as compared to a liquid, for instance.

Plasma -- related to a gas although it has positively charged ions and negatively charged electrons.
pychu [463]3 years ago
5 0

what was the point of deleting my comment... that was irrelevant.

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Which of the following is true about chemical reactions. A. they are accompanied by changes in energy. B. they form new substanc
Ilia_Sergeevich [38]
The correct answer should be option C. hope this helps
7 0
3 years ago
Can someone do my homework pls!
Elza [17]

Answer:

Hi, a cheerful teen willing to help,

wishing you a splendiferous day ahead...

Explanation:

1ai. The most dense is Tungsten.

1aii. The least dense is Sodium.

1aiii. The strongest is Tungsten.

1b. All metals conduct electricity.

They are all magnetic except magnetic.

and all solid at room temperature except mercury.

1c. Mercury is a liquid at room temperature.

1d. Tungsten is used as filament for light bulbs due to its high melting point and it doesn't oxidize, this the filament won't melt.

1e. The lump of gold will sink because it is more dense than mercury.

7 0
3 years ago
Read 2 more answers
If the pressure on a 1.04 L sample of gas is doubled at constant temperature, please compute the new volume of gas: __
natulia [17]

Answer:

0.52 L.

Explanation:

Let P be the initial pressure.

From the question given above, the following data were obtained:

Initial pressure (P1) = P

Initial volume (V1) = 1.04 L

Final pressure (P2) = double the initial pressure = 2P

Final volume (V2) =?

The new volume (V2) of the gas can be obtained by using the the Boyle's law equation as shown below:

P1V1 = P2V2

P × 1.04 = 2P × V2

1.04P = 2P × V2

Divide both side by 2P

V2 = 1.04P /2P

V2 = 0.52 L

Thus, the new volume of the gas is 0.52 L.

6 0
3 years ago
"A crosslinked copolymer consists of 57 wt% ethylene (C2H4) repeat units and 43 wt% propylene (C3H6) repeat units. Determine the
ch4aika [34]

Explanation:

Percentage ethylene by weight = 57%

Percentage propylene by weight = 43%

Suppose in 100 grams of polymer:

Mass of ethylene = 57 g

Mass of propylene = 43 g

Moles of ethylene = \frac{57 g}{28 g/mol}=2.036 mol

Moles of propylene = \frac{43g}{42g/mol}=1.024 mol

1 mole = N_A =6.022\times 10^{23} molecules/ atoms

Units of ethylene = 2.036 mol\times N_A

Units of propylene = 1.024 mol\times N_A

a) Fraction of ethylene units:

=\frac{2.036 mol\times N_A}{2.306 mol\times N_A+1.024 mol\times N_A}=\frac{509}{765}

b ) Fraction of propylene units:

=\frac{1.024mol\times N_A}{2.306 mol\times N_A+1.024 mol\times N_A}=\frac{256}{765}

3 0
3 years ago
A thermometer reads an outside air temperature of 35°c. What is the temperature in degrees Fahrenheit
Hoochie [10]

35°c is equal to 95°f

To do this multiply 35 and 1.8

35 x 1.8=63

Now add 32

Resulting in the answer 95

(The equation for to solve for c and f is c1.8+32=f

3 0
3 years ago
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