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Andreas93 [3]
3 years ago
15

A 4.0-kilogram penguin sliding across a large, flat icy surface with a constant velocity of 2.0 m s–1. Assuming that the surface

is frictionless, what size force is required to keep the penguin travelling at this speed?
Physics
1 answer:
Fiesta28 [93]3 years ago
3 0

Answer:

F=0

Explanation:

Newton's second law states that the sum of the external forces is equal to the product of the mass and the acceleration of the body

         F = m a

in this case it tells us that the velocity is constant so the acceleration must be zero,

therefore the sum of the external forces is zero; as they indicate that the surface is frictionless, there is no force applied to the system to maintain a constant speed

            F = 0

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Which have more kinetic energy a 100g ball,a 200g ball, or a 500g ball explain
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Solar system energy. 700 Grams energy products Ball force
8 0
3 years ago
An object acted on by a constant force F moves from point 1 to point 2 and back again. The work done by the force F in this roun
aksik [14]

Answer:

F is non-conservative.

If F were conservative no work would be done in moving back to the original point.       F dot S = W     if the net distance is zero the work done is zero for a conservative force

7 0
3 years ago
A golf club rotates 215 degrees and has a length (radius) equal to 29 inches. The time it took to swing the club was 0.8 seconds
vichka [17]

Answer:

The average linear velocity (inches/second) of the golf club is 136.01 inches/second

Explanation:

Given;

length of the club, L = 29 inches

rotation angle, θ = 215⁰

time of motion, t = 0.8 s

The angular speed of the club is calculated as follows;

\omega = (\frac{\theta}{360} \times 2\pi, \ rad) \times \frac{1}{t} \\\\\omega =  (\frac{215}{360} \times 2\pi, \ rad) \times \frac{1}{0.8 \ s} \\\\\omega = 4.69 \ rad/s

The average linear velocity (inches/second) of the golf club is calculated as;

v = ωr

v = 4.69 rad/s  x  29 inches

v = 136.01 inches/second

Therefore, the average linear velocity (inches/second) of the golf club is 136.01 inches/second

8 0
3 years ago
Fre.e points ...........
hjlf

Answer:

yooooooooooooooo thanks for the points bestie

7 0
3 years ago
Read the scenario and solve these two problems.
Burka [1]

Answers:

a) 5400000 J

b) 45.92 m

Explanation:

a) The kinetic energy K of an object is given by:

K=\frac{1}{2}mV^{2}

Where:

m=12000 kg is the mass of the train

V=30 m/s is the speed of the train

Solving the equation:

K=\frac{1}{2}(12000 kg)(30 m/s)^{2}

K=5400000 J This is the train's kinetic energy at its top speed

b) Now, according to the Conservation of Energy Law, the total initial energy is equal to the total final energy:

E_{i}=E_{f}

K_{i}+P_{i}=K_{f}+P_{f}

Where:

K_{i}=5400000 J is the train's initial kinetic energy

P_{i}=0 J is the train's initial potential energy

K_{f}=0 J is the train's final kinetic energy

P_{f}=mgh is the train's final potential energy, where g=9.8 m/s^{2} is the acceleration due gravity and h is the height.

Rewriting the equation with the given values:

5400000 J=(12000 kg)(9.8 m/s^{2})h

Finding h:

h=45.918 m \approx 45.92 m

7 0
3 years ago
Read 2 more answers
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