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deff fn [24]
3 years ago
5

Which portion of the electromagnetic spectrum can the human eye detect? *

Physics
1 answer:
Bogdan [553]3 years ago
6 0

Answer:

B. Only wavelengths between infrared and ultraviolet

Explanation:

That is the visible spectrum if you look up a diagram of the light spectrum.

You might be interested in
A person drives a car around a circular cloverleaf with a radius of 77 m at a uniform speed of 10 m/s. What is the acceleration
umka2103 [35]

Answer:

770m/s

Explanation:

caculation using one of the newton law of motion

6 0
3 years ago
Given the reaction: N2(g) +2O2(g) ⇌ 2NO2(g) The forward reaction is endothermic. Determine which of the following changes would
777dan777 [17]

Answer:

A. I and V

Explanation:

According to Le Chatelier's Principle, increasing the product side will cause the equilibrium to shift back towards the reactant side, so I is true.  By the same principle, II is false.

For gases, decreasing the pressure will cause the equilibrium to shift towards the side with higher number of moles.  So V is true.

The reaction is endothermic, so increasing the temperature will shift the equilibrium to the products, so IV is false.  And adding a catalyst has no effect on the equilibrium, so III is false.

7 0
3 years ago
1.A student attaches a string to a puck on a frictionless air table, and pulls with a constant force on the puck. a. Draw the fo
Mrrafil [7]

a)

for the puck :

F = force applied in the direction of pull

N = normal force on the puck in upward direction by the surface of table

W = weight of the puck in down direction due to force of gravity


b)

along the vertical direction , normal force balance the weight of the puck , hence the net force is same as the force of pull F .

so  F = ma                                    where m = mass of puck  , a = acceleration

Fnet = F


c)

since the net force acts in the direction of force of pull F , hence the puck accelerates in the same direction .

6 0
2 years ago
En la figura los émbolos son de masa despreciable y están en reposo, como se ve en la figura, siendo M=300 kg. Determine: a) la
Leni [432]

The image mentioned is in the attachment

Answer: a) P = 2450 Pa;

b) P = 2940 Pa;

c) F = 4.9 N

Explanation:

a) Pressure is a force applied to a surface of an object or fluid per unit area.

The image shows a block applying pressure on the large side of the piston. The force applied is due to gravitation, so:

P = \frac{F}{A}

P = \frac{m.g}{A}

P = \frac{300.9.8}{1.2}

P = 2450 Pa

The pressure generated by the block is P = 2450 Pa.

b) A static liquid can also exert pressure and can be calculated as:

P_{staticfluid} =ρ.g.h

where

ρ is the density of the fluid

h is the depth of the fluid

g is acceleration of gravity

P_{staticfluid} = 600.9.8.0.5

P_{staticfluid} = 2940 Pa

The pressure in the fluid at 50 cm deep is P_{staticfluid} = 2940 Pa.

c) For the system to be in equilibrium both pressures, pressure on the left side and pressure on the right side, have to be the same:

P_{s} = P_{b}

\frac{F}{A_s} = \frac{F_b}{A_b}

F = \frac{F_b}{A_b}.A_s

Adjusting the units, A_{s} = 0.002 m².

F = \frac{300.9.8.0.002}{1.2}

F = 4.9 N

The force necessary to be equilibrium is F = 4.9 N.

4 0
2 years ago
A block is attached to a spring, with spring constant k, which is attached to a wall. it is initially moved to the left a distan
Ghella [55]

Answer:

x(t) = d*cos ( wt )

w = √(k/m)

Explanation:

Given:-

- The mass of block = m

- The spring constant = k

- The initial displacement = xi = d

Find:-

- The expression for displacement (x) as function of time (t).

Solution:-

- Consider the block as system which is initially displaced with amount (x = d) to left and then released from rest over a frictionless surface and undergoes SHM. There is only one force acting on the block i.e restoring force of the spring F = -kx in opposite direction to the motion.

- We apply the Newton's equation of motion in horizontal direction.

                             F = ma

                             -kx = ma

                             -kx = mx''

                              mx'' + kx = 0

- Solve the Auxiliary equation for the ODE above:

                              ms^2 + k = 0

                              s^2 + (k/m) = 0

                              s = +/- √(k/m) i = +/- w i

- The complementary solution for complex roots is:

                              x(t) = [ A*cos ( wt ) + B*sin ( wt ) ]

- The given initial conditions are:

                              x(0) = d

                              d = [ A*cos ( 0 ) + B*sin ( 0 ) ]

                              d = A

                              x'(0) = 0

                              x'(t) = -Aw*sin (wt) + Bw*cos(wt)

                              0 = -Aw*sin (0) + Bw*cos(0)

                              B = 0

- The required displacement-time relationship for SHM:

                               x(t) = d*cos ( wt )

                               w = √(k/m)

3 0
3 years ago
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