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3 years ago

Which detail shows ways that people can help stop Asian carp from spreading?

1 answer:

4 0

So this is asking how they can stop the carp from spreading. A. is talking about the asian carps jumping out of water damage boats but this has nothing to do with what we can do to stop them from spreading!! B. Is saying how when you release the carp into a body of water can cause them to spread even more! so that isnt what we need. C. Is about how plants provide safe places for carps to have more carps and that's what we are trying to stop D. This is saying that we can throw bait we dont want in the trash not the water so when somebody catches an asian carp people know and can not release any more fish to the body of water .

D. - Makes the most sense because it talks about what people can do to stop the spread of the invasive species The Asian Carps

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g Green plants use light from the Sun to drive photosynthesis. Photosynthesis is a chemical reaction in which water and carbon d

LenaWriter [7]

Answer:

6.49g

Explanation:

Let's consider the balanced reaction for photosynthesis.

6 CO₂ + 6 H₂O = C₆H₁₂O₆ + 6 O₂

We can establish the following relations:

1 mole of CO₂ has a mass of 44.01 g (MW 44.01)
The molar ratio of CO₂ to C₆H₁₂O₆ is 6:1.
1 mole of C₆H₁₂O₆ has a mass of 180.16 g/mol.

The mass of glucose produced by the reaction of 9.51 g of carbon dioxide is:

$9.51gCO_2 \times \frac{1molCO_2}{44.01gCO_2} \times \frac{1molGlucose}{6molCO_2} \times \frac{180.16gGlucose}{1molGlucose} = 6.49g Glucose$

6 0

3 years ago

Read 2 more answers

A student chromatographs a mixture and after developing the spots with a suitable reagent he observes the following

Anika [276]

Rf value is the ratio of the distance traveled by the solute to that of the solvent front on the paper used in chromatographic separation.

From the image it is clear the distance traveled by solvent front = 7.3 cm

Distance traveled by the component -1 of the mixture = 1.4 cm

Distance traveled by the component -2 of the mixture = 3.0 cm

Distance traveled by the component -3 of the mixture = 4.5 cm

Distance traveled by the component -4 of the mixture = 6.5 cm

Rf value of component-1 = $\frac{1.4 cm}{7.3 cm} =0.192$

Rf value of component-2 = $\frac{3.0 cm}{7.3 cm} =0.410$

Rf value of component-3 = $\frac{4.5 cm}{7.3 cm} =0.616$

Rf value of component-4 = $\frac{6.5 cm}{7.3 cm} =0.890$

b) Samples can be separated from a mixture using chromatography as the relative affinities for the compounds towards the paper (stationary phase) and the solvent(mobile phase) are different. Each component spends different amounts of time on the stationary phase depending on it chemical nature. So, the components in a mixture can be separated based on their polarities and relative degrees of adsorption on the stationary phase.

6 0

3 years ago

The equilibrium constant for the reaction AgBr(s) Picture Ag+(aq) + Br− (aq) is the solubility product constant, Ksp = 7.7 × 10−

barxatty [35]

Answer:

The reaction will be non spontaneous at these concentrations.

Explanation:

$AgBr(s)\rightarrow Ag^+(aq) + Br^- (aq)$

Expression for an equilibrium constant $K_c$ :

$K_c=\frac{[Ag^+][Br^-]}{[AgCl]}=\frac{[Ag^+][Br^-]}{1}=[Ag^+][Br^-]$

Solubility product of the reaction:

$K_{sp}=[Ag^+][Br^-]=K_c=7.7\times 10^{-13}$

Reaction between Gibb's free energy and equilibrium constant if given as:

$\Delta G^o=-2.303\times R\times T\times \log K_c$

$\Delta G^o=-2.303\times R\times T\times \log K_{sp}$

$\Delta G^o=-2.303\times 8.314 J/K mol\times 298 K\times \log[7.7\times 10^{-13}]$

$\Delta G^o=69,117.84 J/mol=69.117 kJ/mol$

Gibb's free energy when concentration $[Ag^+] = 1.0\times 10^{-2} M$ and $[Br^-] = 1.0\times 10^{-3} M$

Reaction quotient of an equilibrium = Q

$Q=[Ag^+][Br^-]=1.0\times 10^{-2} M\times 1.0\times 10^{-3} M=1.0\times 10^{-5}$

$\Delta G=\Delta G^o+(2.303\times R\times T\times \log Q)$

$\Delta G=69.117 kJ/mol+(2.303\times 8.314 Joule/mol K\times 298 K\times \log[1.0\times 10^{-5}])$

$\Delta G=40.588 kJ/mol$

For reaction to spontaneous reaction: $\Delta G$ .
For reaction to non spontaneous reaction: $\Delta G>0$ .

Since ,the value of Gibbs free energy is greater than zero which means reaction will be non spontaneous at these concentrations

5 0

3 years ago

A pure substance where atoms of two or more elements are chemically bonded to one another

inn [45]

Compound is a pure substance where atoms of two or more elements are chemically bonded togather

8 0

3 years ago

How any moles of H2O will be produced from 12.3 moles of HCL reacting with Ca(OH)2?

stiks02 [169]

Answer:

\large \boxed{\text{12.3 mol HCl}}

Explanation:

We need a balanced chemical equation with moles.

2HCl +Ca(OH)₂ ⟶ CaCl₂ + 2H₂O

n/mol: 12.3

The molar ratio is 2 mol H₂O:2 mol HCl.

$\text{Moles of H$_{2}$O} = \text{12.3 mol HCl} \times \dfrac{\text{2 mol H$_{2}$O}}{\text{2 mol HCl}} = \textbf{12.3 mol HCl}\\\\\text{The reaction produces $\large \boxed{\textbf{12.3 mol HCl}}$}$

3 0

3 years ago