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Oduvanchick [21]
3 years ago
11

What do lysosomes and Golgi bodies have in common?

Chemistry
2 answers:
ser-zykov [4K]3 years ago
6 0
The answer is B ribosomes
Drupady [299]3 years ago
5 0
The first question would be B) they are examples of cell organelles. The second question would be A) mitochondria. Hope this helps!
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What was the name of the disease that killed nearly half the people of Europe?
Licemer1 [7]
The answer is the plague, or the black death
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3 years ago
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Which of the following substances are largely ionic?
Vesna [10]
The substances largely ionic are:

NF3
N2
BrF3
PCl3
5 0
3 years ago
Aspirin is the common name for acetyl salicylic acid, C9H8O4. One tablet contains 0. 325 g of aspirin. How many moles of aspirin
marin [14]

Answer:

.0017952905 mol

Explanation:

I hope this helps, I can't promise I got it right, please let me know haha!

5 0
2 years ago
Consider the partial equation. Br2 + NaF --> Which best completes the chemical equation?
balandron [24]

Answer is (1) - no reaction.


<em>Explanation; </em>


Some of you may think this reaction as a single replacement reaction which gives NaBr + F₂ as products.


But, according to the reactivity of the halogens, reactivity decreases from up to bottom of the group. F is placed above Br. Hence, F is more reactive than Br. Hence, Br can't replace F.




5 0
3 years ago
Read 2 more answers
The equilibrium constant, Kc, is calculated using molar concentrations. For gaseous reactions another form of the equilibrium co
Anarel [89]

Answer:

Kp = 1.41 x 10⁻⁶

Explanation:

We have the chemical equation:

2 A(g) + 3 B(g)⇌ C(g)

In which A and B are the reactants and C is the product. We calculate first the change in the number of moles of gas (Δn or dn):

dn= (sum moles products - sum moles reactants)

   = (moles C - (moles A + moles B))

   = (1 - (2+3))

   = 1 - 5

   = -4

We have also the following data:

Kc = 63.2

T= 81∘C + 273 = 354 K

R = 0.082 L.atm/K.mol (it is a constant)

Thus, we introduce the data in the mathematical expression for the relation between Kp and Kc:

Kc = (RT)^{dn}= (0.082 L.atm/K.mol x 354 K)⁻⁴ = 1.41 x 10⁻⁶

3 0
3 years ago
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