PPRR, PpRR, PPRr, and PpRr
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Answer : To calculate the number of moles of copper (II) chloride in 15.0 ml of 0.500 M solution, you have to simply use the given calculation:
15 (ml) X 0.500 (moles) / 1000 (mL) = <span>0.00750 moles of CuCl₂ .
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Using the formula 2n² put in the value of n which is 4
the answer is 2×4² which is 2×16
The answer is 32.
this is the maximum no of electron acceptable into the electron shell.
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