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xenn [34]
3 years ago
8

A relationship in which one variable increases as the other variable decreases is an inverse relationship.

Chemistry
1 answer:
Brut [27]3 years ago
8 0

Answer:

TRUE

Explanation:

HOPE IT WILL HELP YOU

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A forward reaction in which adding heat decreases product formation is _________, while a forward reaction in which adding heat
ELEN [110]
I believe the correct answer from the choices listed above is option A. <span>A forward reaction in which adding heat decreases product formation is exothermic, while a forward reaction in which adding heat increases product formation is endothermic. Exothermic would mean that heat is being released by the process while the opposite is called endothermic in which it absorbs heat.</span>
3 0
4 years ago
Why would an aqueous solution of a strong electrolyte conduct electricity better than an aqueous solution of a weak electrolyte?
Virty [35]
The answer is B because the more ions the more electrolytes it has
4 0
4 years ago
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One beaker contains 100 mL of pure water and second beaker contains 100 mL of seawater. The two beakers are left side by side on
gayaneshka [121]

Explanation:

When we add a non-volatile solute in a solvent then due to the impurity added to the solution there will occur an increase in the boiling point of the solution.  

This increase in boiling point will be known as elevation in boiling point.

As one beaker contains seawater (water having NaCl) will have some impurity in it. So, more temperature is required by seawater to escape into the atmosphere.

Whereas another beaker has only pure water so it is able to easily escape into the atmosphere since, it contains no impurity.

Thus, we can conclude that level of pure water will decrease more due to non-volatile solute present in it as compared to seawater.

7 0
3 years ago
Neptunium-237 undergoes a series of α-particle and β-particle productions to end up as thallium-205. How many α particles and β
Fantom [35]
<h3>Answer:</h3>

8 alpha particles

4 beta particles

<h3>Explanation:</h3>

<u>We are given;</u>

  • Neptunium-237
  • Thallium-205
  • Neptunium-237 undergoes beta and alpha decay to form Thallium-205.

We are required to determine the number of beta and alpha particles produced to complete the decay series.

  • We need to know that when a radioisotope emits an alpha particle the mass number reduces by 4 while the atomic number decreases by 2.
  • When a beta particle is emitted the mass number of the radioisotope increases by 1 while the atomic number remains the same.

In this case;

Neptunium-237 has an atomic number 93, while,

Thallium-205 has an atomic number 81.

Therefore;

²³⁷₉₃Np → x⁴₂He + y⁰₋₁e + ²⁰⁵₈₁Ti

We can get x and y

237 = 4x + y(0) + 205

237-205 = 4x

4x = 32

 x = 8

On the other hand;

93 = 2x + (-y) + 81

but x = 8

93 = 16 -y + 81

y = 4

Therefore, the complete decay equation is;

²³⁷₉₃Np → 8⁴₂He + 4⁰₋₁e + ²⁰⁵₈₁Ti

Thus, Neptunium-237 emits 8 alpha particles and 4 beta particles to become Thallium-205.

5 0
3 years ago
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vlabodo [156]

Answer:

1. Delete lion, bison, reindeer, and giraffe

2. Delete cactus, oak, evergreen,

Explanation:

1. Lions live in the African savanna, bison live in open fields with lots of grass, reindeer live in Antarctica and other very cold places, and giraffes also live in the areas of the African savanna where there are trees.

2. Cacti live in the desert, oaks and evergreens live in open grassy areas.

Hope this helps

5 0
3 years ago
Read 2 more answers
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