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Lostsunrise [7]
2 years ago
12

Emmett is lifting a box vertically. Which forces are necessary for calculating the total force?

Chemistry
1 answer:
alexandr1967 [171]2 years ago
8 0

Emmett is lifting a box vertically. The forces that are necessary for calculating the total force is Fp and Fg. The correct option is D.

<h3>What is force?</h3>

Force is an influence or strength that is used to initiate an action or movement. There are total eight types of forces are present.

Fp is the applied force and Fg is the force of gravitation, if Emmett is lifting a box vertically, these force will be applied

Thus, the correct option is D, Fp and Fg.

Learn more about force

brainly.com/question/13191643

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Answer:

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5 0
3 years ago
Is the answer B? Help
Masja [62]

Answer:

A

Explanation:

Hmm, so we have the following in the diagram

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Anode definition: the positively charged electrode by which the electrons leave an electrical device.

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7 0
3 years ago
At an elevated temperature, Kp=4.2 x 10^-9 for the reaction 2HBr (g)---&gt; +H2(g) + Br2 (g). If the initial partial pressures o
Damm [24]

Answer : The partial pressure of H_2 at equilibrium is, 1.0 × 10⁻⁶

Explanation :

The partial pressure of HBr = 1.0\times 10^{-2}atm

The partial pressure of H_2 = 2.0\times 10^{-4}atm

The partial pressure of Br_2 = 2.0\times 10^{-4}atm

K_p=4.2\times 10^{-9}

The balanced equilibrium reaction is,

                                2HBr(g)\rightleftharpoons H_2(g)+Br_2(g)

Initial pressure    1.0×10⁻²       2.0×10⁻⁴      2.0×10⁻⁴

At eqm.            (1.0×10⁻²-2p)   (2.0×10⁻⁴+p)  (2.0×10⁻⁴+p)

The expression of equilibrium constant K_p for the reaction will be:

K_p=\frac{(p_{H_2})(p_{Br_2})}{(p_{HBr})^2}

Now put all the values in this expression, we get :

4.2\times 10^{-9}=\frac{(2.0\times 10^{-4}+p)(2.0\times 10^{-4}+p)}{(1.0\times 10^{-2}-2p)^2}

p=-1.99\times 10^{-4}

The partial pressure of H_2 at equilibrium = (2.0×10⁻⁴+(-1.99×10⁻⁴) )= 1.0 × 10⁻⁶

Therefore, the partial pressure of H_2 at equilibrium is, 1.0 × 10⁻⁶

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