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Lostsunrise [7]
2 years ago
12

Emmett is lifting a box vertically. Which forces are necessary for calculating the total force?

Chemistry
1 answer:
alexandr1967 [171]2 years ago
8 0

Emmett is lifting a box vertically. The forces that are necessary for calculating the total force is Fp and Fg. The correct option is D.

<h3>What is force?</h3>

Force is an influence or strength that is used to initiate an action or movement. There are total eight types of forces are present.

Fp is the applied force and Fg is the force of gravitation, if Emmett is lifting a box vertically, these force will be applied

Thus, the correct option is D, Fp and Fg.

Learn more about force

brainly.com/question/13191643

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In an aquarium the water quantity is limited and fish excrete ammonia through their gills and body, this dissolves in water and creates toxins.

<u>Explanation</u>:

  • In an aquarium the water quantity is limited and fish excrete ammonia through their gills and body, this dissolves in water and creates toxins. Over some time some bacteria develop in water which converts this ammonia into nitrites and then into nitrates. Till this process is complete, the aquarium remains a death trap.

There are some reasons for a fish to die early,

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Sodium peroxide (Na2O2) is often used in self-contained breathing devices, such as those used in fire emergencies, because it re
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Answer:

725.15 L

Explanation:

The balanced chemical equation for the reaction between Na₂O₂ and CO₂ is the following:

Na₂O₂ + CO₂ → Na₂CO₃ + 1/2 O₂

From the stoichiometry of the reaction, 1 mol of Na₂O₂ reacts with 1 mol CO₂. So, the stoichiometric ratio is 1 mol Na₂O₂/1 CO₂.

Now, we convert the mass of reactants to moles by using the molecular weight (Mw) of each compound:

Mw (Na₂O₂) = (23 g/mol x 2) + (16 g/mol x 2) = 78 g/mol

moles Na₂O₂ = 96.7 g/(78 g/mol) = 1.24 mol Na₂O₂

Mw (CO₂) = 12 g/mol + (16 g/mol x 2) = 44 g/mol

moles CO₂ = 0.0755 g/(44 g/mol) = 1.71 x 10⁻³ mol CO₂

Now, we calculate the number of moles of CO₂ we need to completely react with the mass of Na₂O₂ we have:

1.24 mol Na₂O₂ x 1 mol CO₂/1 mol Na₂O₂ = 1.24 mol CO₂

In 1 L of respired air we have 1.71 x 10⁻³ mol CO₂ (0.0755 g), so we need the following number of liters to have 1.24 mol of CO₂:

1.24 mol CO₂ x 1 L/1.71 x 10⁻³ mol CO₂ = 725.15 L

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