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Mumz [18]
3 years ago
5

Can someone please help me with this question and I will give you brainlest

Physics
2 answers:
grigory [225]3 years ago
7 0

Answer:

PEENNISS

Explanation:

navik [9.2K]3 years ago
5 0
Answer: 50%
Hope this helped
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Jupiter's semimajor axis is 7.78×1011 m. The mass of the Sun is 1.99×1030 kg. (a) What is the period of Jupiter's orbit in secon
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Explanation:

It is given that,

Semi major axis of the Jupiter, a=7.78\times 10^{11}\ m

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T^2\propto a^3

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T^2=\dfrac{4\pi^2}{6.67\times 10^{-11}\times 1.99\times 10^{30}}\times (7.78\times 10^{11})^3

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(b) We know that,

1\ year=3.154\times 10^7\ s

or

1\ s=3.171\times 10^{-8}\ year

3.74\times 10^8\ s={3.171\times 10^{-8}}\times {3.74\times 10^8}

T = 11.859 earth years

Hence, this is the required solution.

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4 years ago
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Cellular telephone use
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Answer:

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Explanation:

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