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Eva8 [605]
3 years ago
11

The initial vertical component of the velocity is 15.3 m/s and the angle of the water is 55 degrees. What is the magnitude of th

e vector?
The answer is 18.7 m/s but how did they get this???
Physics
1 answer:
Alex787 [66]3 years ago
3 0

The vertical component of velocity is given by

V = Vy x Sin (Theta)

15.3 m/s = Vy x Sin (55 degrees)

Vy = 15.3 m/s/Sin (55 degrees)

= 15.3 m/s/0.819

= 18.681 m/s

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Answer:

The near point of an eye with power of +2 dopters, u' = - 50 cm

Given:

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To calculate the near point, we need to find the focal length of the lens which is given by:

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Thus

f = \frac{1}{P}

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Now, by using lens maker formula:

\frac{1}{f} = \frac{1}{u} + \frac{1}{u'}

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Now,

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Solving the above eqn, we get:

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