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1. Two wires - A and B - with circular cross-sections have identical lengths and are made of the same material. Yet, wire A has

PolarNik [594]

Answer:

Diameter of wire B is 2 times the diameter of wire A

Explanation:

We have given two wire A and B

They are made up of same material and length of both the wire is sane

So $l_A=l_B$

Let the resistivity of both the wire is $\rho$

It is given that wire A has 4 times the resistance as wire B

So $R_A=4R_B$

So $\frac{\rho l_A}{a_A}=4\frac{\rho l_B}{a_B}$ ( As $l_A=l_B$ )

$\frac{a_A}{a_B}=\frac{1}{4}$

$\frac{d_A^2}{d_B^2}=\frac{1}{4}$

$\frac{d_A}{d_B}=\frac{1}{2}$

$d_B=2d_A$

So diameter of wire B is 2 times the diameter of wire A

6 0

2 years ago

Where is the planet moving faster?

valentinak56 [21]

Answer:

I looked it up but got perihelion so I don't know if that will help at all but try um.... I don't know try L

Explanation:

7 0

2 years ago

PHYSICS

quester [9]

Answer:

c) 8.3 x 10^24 molecules

Explanation:

First of all, we convert the volume of the glass of water from mL to $cm^3$ :

$V=250 mL = 250 cm^3$

The relationship between mass and volume is:

$d=\frac{M}{V}$

where

$d=1.00 g/cm^3$ is the density of water

M is the total mass of the glass of water

$V=250 cm^3$ is the volume of the water in the glass

Solving for M,

$M=dV=(1.00)(250)=250 g = 0.250 kg$

Now we know that the mass of a single molecule of water is

$m=3.0\cdot 10^{-26}kg$

The total mass of the water in the glass can be written as

$M=Nm$

where

N is the number of molecules in the glass of water

Solving for N, we find:

$N=\frac{M}{m}=\frac{0.250}{3.0\cdot 10^{-26}}=8.3\cdot 10^{24}$

7 0

2 years ago

abody starts from rest and accelerate uniformly at 8m/s/s.calculate the distance travelled by the body in 10s?

vagabundo [1.1K]

Explanation:

using the formula: S=ut+½gt², where u=0, S=?, g=8m/s², t=10seconds.

S=ut+½gt² ("ut" term will cancel because u=0).

=> S= ½gt²

=>S = ½×8×10²

=>S = 4×100

=>S = 400m .

Therefore, the distance traveled by the body in 10s is 400m.

hope this helps you.

6 0

2 years ago

La luz roja visible tiene una longitud de onda de 680 nanómetros (6,8 x 10-7 m). La velocidad de la luz es de 3.0 x108 m / s. ¿C

Lina20 [59]

Answer:

Frequency, $f=4.41\times 10^{14}\ Hz$

Explanation:

Visible red light has a wavelength of 680 nanometers (6.8 x 10⁻⁷ m). The speed of light is 3.0 x 10 ⁸ m / s. What is the frequency of visible red light?

It is given that,

Wavelength of a visible red light is, $\lambda=6.8\times 10^{-7}\ m$

Speed of light is, $c=3\times 10^8\ m/s$

We need to find the frequency of visible red light. It can be calculated using below relation.

$c=f\lambda\\\\f=\dfrac{c}{\lambda}\\\\f=\dfrac{3\times 10^8}{6.8\times 10^{-7}}\\\\f=4.41\times 10^{14}\ Hz$

So, the frequency of visible red light is $4.41\times 10^{14}\ Hz$ .

3 0

2 years ago