Answer:
a = 16 m/s²
Explanation:
Given that,
Initial speed of a roler coaster, v₁ = 6 m/s
Final speed of a roller coaster, v₂ = 70 m/s
Time, t = 4s
We know that, acceleration of an object is equal to the rate of change of velocity. Let the acceleration be a. Its formula is given by :
or
The correct option is (1). Its value is equal to :
Its value is equal to 16 m/s².
Answer:
Ordinal
Explanation:
There are four levels of measurement which include the nominal, ordinal, interval, and ratio. The data collected above is ordinal data as it qualifies the data and still indicates the ordering of the data. It gives the observer an idea of the range of data collected or its rating although mathematical calculations may not be done with it.
The other forms of data include the nominal which simply qualifies the data, the interval which qualifies the data but which the differences between the data can be obtained, and of course the data has no starting point. The ratio scale which is similar to the interval scale but which the ratios between the data obtained can be compared.
Answer:
A. 19.8 cm.
Explanation:
The apparent depth of the combination is
As it mentioned that the two clear but non-mixing liquid having depth of 15 cm that placed in a glass container together
Also the refractive indices would be 1.75 and 1.33
Based on the above information
As we know that
Refractive indices = real depth ÷ apparent depth
1.33 ÷ 1.75 = 15 ÷ apparent depth
So, it would be 19.736842 cm
Now the combination of apparent depth would be
= ( 19.736842 + 15) ÷ (1.75)
= 19.8 cm
hence, the correct option is A.
Incomplete question.The complete one is here
Spacecraft have been sent to Mars in recent years. Mars is smaller than Earth and has correspondingly weaker surface gravity. On Mars, the free-fall acceleration is only 3.8m/s2. What is the orbital period of a spacecraft in a low orbit near the surface of Mars?
Answer:
Explanation:
Given
To find
orbital period of a spacecraft T
Solution
An the initial calculating is computing the angular velocity of satellite :
Computing T