10.4 N
Given
m = 1.10 kg
θ = 15.0°
g = 9.81 m/s2
Solution
Fnet, y = ΣF y = Fn − Fg, y = 0
Fn = Fg, y = Fg
cosθ = mgcosθ
Fn = (1.10 kg)(9.81 m/s2
)(cos15.0°) = 10.4 N
Answer: The acceleration for the shuttle is 13 800m/s^2.
Explanation:
The answer is required is si unit which is m/s^2.
The first step is to convert to velocity to m/s, 1km=1000m therefore we have to multiply by 1000
5km/s=5000m/s
11.9km/s=11900m/s.
The formula for the acceleration is a=dv/t
a=11900-5000/0.5
a=13 800m/s
Explanation:
Mass of the crate, m = 68 kg
We need to find the resulting acceleration if :
(a) Force, P = 0
P = m a
⇒ a = 0
(b) P = 181 N
(c) P = 352 N
Hence, this is the required solution.
