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3 years ago

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Physics

2 answers:

Lesechka [4]3 years ago

4 0

Planets in motion will have a constant speed unless acted on by an outside force (c)

seraphim [82]3 years ago

3 0

Explanation:

that's just what I learned in school

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Of the numbers 0.0034 m, 45.6 m, and 1234 m, which is the most precise?

julia-pushkina [17]

Answer:

The most precise is 0.0034 m ⇒ 1st answer

Explanation:

Lets revise the meaning of precise

Precision is referred as the closeness of two measurements to one

another.

Highest number with significant digit is the most precise

Ex: Highest significant of optical instrument is the Wavelength of visible (red)

light = 0.00006 cm

Hence the most precise device for measuring length is the given optical

instrument

The difference between accuracy and precise

Accuracy is how close a value is to its true value

Precision is how repeatable a measurement is

We have three numbers

0.0034 m, 45.6 m, and 1234 m

The least precise is 1234 m

The most precise is 0.0034 m

4 0

3 years ago

Read 2 more answers

Marissa keeps track of all attendance records for the local preschool. Which

stiks02 [169]

Answer: C and A

Explanation: a p e x :)

Fllw me on ig (Kyojei)

3 0

3 years ago

Read 2 more answers

A thin, uniformly charged insulating rod has a linear charge density λ = 3 nC/m and lies along the x axis from x = 1m to x = 3m.

Contact [7]

Answer:

A) $V_A = 11.93~V$

B) The vector definition of E-field is

$\vec{E} = -1.13\^x + 2.41\^y$

where magnitude is E = 2.66 N/m.

Explanation:

The potential of a uniformly charged rod can be found by the method of integration. We will first choose an infinitesimal part on the rod. We will compute the potential of this part at point A. Then we will integrate this potential over the entire rod.

We will use the following formula for electric potential:

$V = \frac{1}{4\pi \epsilon_0}\frac{Q}{r}$

Let us choose the infinitesimal part a distance 'x' from the origin. Then the distance between this point and point A is

$r = \sqrt{x^2+4^2}$

The infinitesimal length is 'dx', and the potential of this length is dV. Let's apply the formula:

$dV = \frac{1}{4\pi\epsilon_0}\frac{\lambda dx}{\sqrt{x^2 + 4^2}}$

Here, the charge Q is equal to the charge density multiplied by the length. Q = λdx

Now we have to integrate this infinitesimal potential over the rod:

$V = \int\limits^3_1 {dV} \, dx = \frac{1}{4\pi \epsilon_0}\int\limits^3_1 {\frac{\lambda}{\sqrt{x^2 + 16}} \, dx$

By using an integral table, this can be calculated:

$V = \frac{3\times 10^{-9}}{4\pi\epsilon_0}\ln(|\sqrt{x^2+16}+x|)\left \{ {{x=3} \atop {x=1}} \right. \\V = 11.93~V$

B) The electric field can be found by a similar approach, but a different formula:

$\vec{E} = \frac{1}{4\pi \epsilon_0}\frac{Q}{r^2}\^r$

Let's apply this formula to the infinitesimal part we have chosen.

$dE_x = \frac{1}{4\pi\epsilon_0}\frac{\lambda dx}{x^2 + 4^2}\cos(\theta)\\dE_y = \frac{1}{4\pi\epsilon_0}\frac{\lambda dx}{x^2 + 4^2}\sin(\theta)$

By the geometry sine and cosine terms can be found:

$\sin(\theta) = \frac{4}{\sqrt{x^2+16}}\\\cos(\theta) = \frac{x}{\sqrt{x^2 + 16}}$

The x- and y-components of the E-field can be found separately by integrating the infinitesimal parts over the entire rod.

$E_x = \int\limits^3_1 {dE_x} \, dx = \frac{\lambda}{4\pi\epsilon_0}\int\limits^3_1 {\frac{x}{(x^2+16)^{3/2}}} \, dx = 1.13(-\^x)\\E_y = \int\limits^3_1 {dE_y} \, dx = \frac{4\lambda}{4\pi\epsilon_0}\int\limits^3_1 {\frac{1}{(x^2+16)^{3/2}}} \, dx = 2.41(\^y)$

So, the final E-field is

$\vec{E} = -1.13\^x + 2.41\^y$

The magnitude of the E-field is

E = 2.66 N/m

6 0

3 years ago

a student solving for the acceleration of an object has applied appropriate physics principles and obtained the expression a

kozerog [31]

Given:

$Force, f = 12 \frac{kg-m}{sec^{2} }$

$Mass, m = 7 kg$

$Acceleration, a_{1} = 3\;\frac{m}{sec^{2} }$

$a = a_{1}+\frac{f}{m}$

$Substitute\;the\;values\;of\;f,\;m\;and\;a_{1}\;in\;the\;above\;equation,$

$a = 3+\frac{12}{7}$

$a = 3 + 1.714$

Therefore, the acceleration is,

$a = 4.714\;\frac{m}{sec^{2} }$

<h3>Explain Acceleration?</h3>

An object's rate of changing its velocity is known as its acceleration, which is a vector quantity. If an object's velocity is changing, it is accelerating. When anything moves faster or slower in a straight line, it is said to have been accelerated. Even if the speed is constant, motion on a circle accelerates because the direction is always shifting.

To learn more about Acceleration, visit:

brainly.com/question/12550364

#SPJ4

3 0

1 year ago

If a box of supplies is dropped from the cargo hold of an airplane travelling at an altitude of 4,410 meters how long will it ta

Paraphin [41]

Answer:

It will take 30 seconds to reach the ground, and it will be travelling at 294 m/s when it does so. This means that its average velocity was 147 m/s.

Explanation:

$d=v_ot+\dfrac{1}{2}at^2$